如何模拟控制器中定义的$ rootScope方法?

时间:2016-02-15 13:49:52

标签: angularjs unit-testing mocking jasmine

我正在为服务编写单元测试并且遇到 $ rootScope.hideLogout(); 方法的问题(请参阅下面的服务代码),因为它是在控制器中定义的而我不是从我的测试中访问(至少我是这么认为)这个控制器,我收到错误:

  

对象不支持属性或方法'hideLogout'

这是我的测试:

it('should logout when player is in the system', function () {
        var user = {
            name: 'player name',
            password: 'password'
        };
        var userData = {
            access_token: 'token',
            token_type: 'bearer',
            expires_in: 1209599,
            userName: 'Player@maildomain.com',
            issued: "Fri, 12 Feb 2016 12:02:37 GMT",
            expires: 'Thu, 25 Feb 2016 13:22:45 GMT',
            userId: 2,
            accountType: 'Player',
            certifiedForAccess: true
        }
        localStorage.setItem('userAuth', JSON.stringify(user));
        localStorage.setItem('tokenKey', JSON.stringify(userData));
        localStorage.setItem('userId', userData.userId);

        authSvc.logOut(true, function() {}); // not sure about callback, so decided to put empty function for now
        var resultToken = localStorage.getItem('tokenKey');

        expect(localStorage.getItem('tokenKey')).toBeNull();
        expect(localStorage.getItem('userAuth')).toBeNull();
        expect(localStorage.getItem('userId')).toBeNull();
    });

我的 beforeEach()功能:

beforeEach(function() {

    module('app');
    inject(function (_AuthService_, $q, $rootScope, $httpBackend, $state, _config_, _messages_) {
        scope = $rootScope;

        authSvc = _AuthService_;
        httpBackend = $httpBackend;
        config = _config_;
    });
});

要测试的服务方法:

function logOut(logoutAnyway, cancelLogoutCallback) {
        if (logoutAnyway || !svc.isAdministrator()) {
            $rootScope.hideLogout(true);
            localStorage.removeItem(userIdKey);
            localStorage.removeItem(userAuthKey);
            localStorage.removeItem(tokenKey);
            $state.go('login');
            svc.fakeUserId = null;
        } else {
            $rootScope.showLogout(cancelLogoutCallback);
        }
    }

你能指点一下如何处理它吗?

1 个答案:

答案 0 :(得分:0)

尝试在测试中使用scope = $rootScope.new()

<强>更新

您还需要使用Jasmine的spyOn方法。

spyOn(scope , 'hideLogout');
spyOn(scope , 'showLogout');

更新2

scope = $rootScope.new()尝试模拟$rootScope

上的两个方法之后
scope.hideLogout = function () {};
scope.showLogout = function () {};

然后添加代码的spyOn部分

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