Question

我一直在尝试应对这一挑战。它最终使用过去的日期，它给了我想要的格式（年，月，日），但不适用于将来的日期。我如何重做这个例子，所以它也适用于未来的日期？截至目前，我得到一个空字符串。

Answer 1

您只需使用Math.abs()获取yearsDiff

即可

function reworkedInBetweenDays(year, month, day) {

   var today = new Date();

   var fromdate = new Date(year, month - 1, day);

   var yearsDiff = Math.abs(today.getFullYear() - fromdate.getFullYear()); //HERE
   var monthsDiff = today.getMonth() - fromdate.getMonth();
   var daysDiff = today.getDate() - fromdate.getDate();

   if (monthsDiff < 0 || (monthsDiff === 0 && daysDiff < 0))
      yearsDiff--;
   if (monthsDiff < 0)
      monthsDiff += 12;

   if (daysDiff < 0) {
      var fromDateAux = fromdate.getDate();
      fromdate.setMonth(fromdate.getMonth() + 1, 0);
      daysDiff = fromdate.getDate() - fromDateAux + today.getDate();
      monthsDiff--;
   }

   var result = [];

   if (yearsDiff > 0)
      result.push(yearsDiff + (yearsDiff > 1 ? " years" : " year"));
   if (monthsDiff > 0)
      result.push(monthsDiff + (monthsDiff > 1 ? " months" : " month"));
   if (daysDiff > 0)
      result.push(daysDiff + (daysDiff > 1 ? " days" : " day"));

   return result.join(', ');

}

console.log(reworkedInBetweenDays(2013, 4, 8));
console.log(reworkedInBetweenDays(2014, 1, 16));
console.log(reworkedInBetweenDays(2016, 1, 31));
console.log(reworkedInBetweenDays(2017, 2, 16));

Answer 2

它可以在最后添加此代码

if (yearsDiff < 0)
  result.push(yearsDiff*(-1) + (yearsDiff*(-1) > 1 ? " years in the future" : " year in the future"));
if (monthsDiff < 0)
  result.push(monthsDiff*(-1) + (monthsDiff*(-1) > 1 ? " months in the future" : " month in the future"));
if (daysDiff < 0)
  result.push(daysDiff*(-1) + (daysDiff*(-1) > 1 ? " days in the future" : " day  in the future"));

Answer 3

monthsDiff和daysDiff都为零且yearsDiff为-1，这意味着它们都没有在底部设置if语句。当所有这些值为零或负值时，您需要添加一些代码来处理。

返回未来日期 - Javascript（年，月，日）

3 个答案: