Hangman程序故障

时间:2016-02-19 06:16:57

标签: python

我在这里是全新的,据我所知,没有人问过我的具体问题。如果有人有,请随时将我与问题联系起来。

无论如何,我正在阅读一本关于python book(发明你自己的电脑游戏)的发明,并且我正试图完成" Hangman"章节。我遇到的问题是,每当我输入一封信时,无论是否正确,该程序仍然会绘制刽子手的碎片。我目前正在运行Python 3,该书正在使用它。这是我的代码:

import random
HANGMANPICS = ['''

 +---+
 |  |
    |
    |
    |
    |
===========''','''

 +---+
 |  |
 O  |
    |
    |
    |
===========''','''

+---+
 |  |
 O  |
 |   |
    |
    |
===========''','''

+---+
 |  |
 O  |
/|   |
    |
    |
===========''','''

+---+
 |  |
 O  |
/|\ |
    |
    |
===========''','''

+---+
 |  |
 O  |
/|\ |
/   |
    |
===========''','''

+---+
 |  |
 O  |
/|\ |
/ \ |
    |
===========''']

words = 'ant baboon badger bat bear beaver camel cat clam cobra cougar \
coyote crow deer dog donkey duck eagle ferret fox frog goat goose hawk \
lion lizard llama mole monkey moose mouse mule newt otter owl panda parrot \
pigeon python rabbit ram rat raven rhino salmon seal shark sheep skunk sloth \
snake spider stork swan tiger toad trout turkey turtle weasel whale wolf wombat\
zebra'.split()

def getRandomWord(wordList):

    wordIndex = random.randint(0, len(wordList)- 1)
    return wordList[wordIndex]

def displayBoard(HANGMANPICS, missedLetters, correctLetters, secretWord):
    print(HANGMANPICS[len(missedLetters)])
    print()

    print('Missed letters:', end ='')
    for letter in missedLetters:
        print(letter, end = '')
    print()

    blanks = '_' * len(secretWord)

    for i in range(len(secretWord)):
        if secretWord[i] in correctLetters:
            blanks = blanks[:i] + secretWord[i] + blanks[i+1:]

    for letter in blanks:
        print(letter, end = '')
    print()

def getGuess(alreadyGuessed):

    while True:
        print('Guess a letter.')
        guess = input()
        guess = guess.lower()
        if len(guess) != 1:
            print('Please enter a single letter')
        elif guess in alreadyGuessed:
            print('You have already guessed that letter. Choose again.')
        elif guess not in 'abcdefghijklmnopqrstuvwxyz':
            print('Please enter a LETTER')
        else:
            return guess

def playAgain():

    print('Do you want to play again?(yes or no)')
    return input().lower().startswith('y')

print('H A N G M A N')

missedLetters = ''
correctLetters = ''
secretWord = getRandomWord(words)
gameIsDone = False

while True:
    displayBoard(HANGMANPICS, missedLetters, correctLetters, secretWord)

    guess = getGuess(missedLetters + correctLetters)

    if guess in secretWord:
        correctLetters = correctLetters + guess

        foundAllLetters = True

    for i in range(len(secretWord)):
        if secretWord[i] not in correctLetters:
            foundAllLetters = False
            break

    if foundAllLetters:
        print('Yes! The secret word is "'+ secretWord +'"! You have won!')
        gameIsDone = True
    else:
        missedLetters = missedLetters + guess

    if len(missedLetters) == len(HANGMANPICS) -1:
        displayBoard(HANGMANPICS, missedLetters, correctLetters, secretWord)
        print('You have run out of guesses!\nAfter ' + str(len(missedLetters)) + ' missed guesses and ' + str(len(correctLetters))+ ' correct guesses, the word was "'+ secretWord +'"')
        gameIsDone = True

    if gameIsDone:
        if playAgain():
            missedLetters = ''
            correctLetters = ''
            gameIsDone = False
            secretWord = getRandomWord(words)
        else:
            break

1 个答案:

答案 0 :(得分:1)

主要问题在于您为丢失的信件设置了条件 - 即使是正确的猜测也会被视为错过的字母'。

在您的代码中:

else:
    missedLetters = missedLetters + guess
在原始检查字母是否在单词之后,

还有很长的路要走。

如果将子句移动到此处,则可以正常工作:

if guess in secretWord:
    correctLetters = correctLetters + guess
    foundAllLetters = True

else:
    missedLetters = missedLetters + guess

在这种情况下,只有当错误的字母不在secretWord中时,它才会被添加到错过的字母列表中。

随着这种变化,事情似乎对我来说没问题。

相关问题