从表A中获取不同的行，这些行是表B中的不同列值

Question

在SQL server中，我有以下表格（它们是简化的）：

表A：

ID| NAME | ID_STATUS | STATUS
--------------------------------
1 | One  | 1         | Confirmed 
2 | Two  | 2         | Pending 
3 | Three| 0         | Deleted 
4 | Four | 1         | Confirmed 

表B（详见A）：

ID (same from A) | NAME | ID_STATUS | STATUS
-----------------------------------------------
1                | One  | 1         | Confirmed
1                | One  | 1         | Confirmed
2                | Two  | 2         | Pending
3                | Three| 2         | Pending
3                | Three| 2         | Pending
4                | Four | 2         | Pending

我需要从A获取不同的行（ID，NAME，ID_STATUS，STATUS），其中（ID_STATUS，STATUS）与B不同

预期结果：

ID | NAME | ID_STATUS | STATUS
---------------------------------
3  | Three| 0         | Deleted
4  | Four | 1         | Confirmed

我试图通过LEFT OUTER JOIN尝试没有成功...（返回0结果）

select A.ID, A.NAME, A.ID_STATUS, A.STATUS from A left outer join B
   on A.ID = B.ID
   where
      A.ID_STATUS != B.ID_STATUS

Answer 1

select A.ID, A.NAME, A.ID_STATUS, A.STATUS 
from A 
left outer join B
      on A.ID        = B.ID 
     and A.ID_STATUS = B.ID_STATUS
where b.ID is null 

Answer 2

选择A.ID，A.NAME，A.ID_STATUS，A.Acol来自A左外连接B A.ID = B.ID和A.ID_STATUS = B.ID_STATUS其中B.ID为空;