Question

所以我目前有一个包含8列的MySQL表，其中的问题看起来有点类似于用于收集回复的问题。每个问题的响应范围为1-5作为值。：

id | q1-q8 |时间戳

我现在正在尝试创建一个摘要表，打破每个问题的回复。

我在MySQL中使用count()和GROUP BY玩弄了一点但没有取得真正的成功。所以我以手动的方式展示了这一点，看起来有点像这样：

<?php
//connect to db


$count1_1 = mysql_num_rows(mysql_query("SELECT q1 FROM table WHERE q1=1"));
$count1_2 = mysql_num_rows(mysql_query("SELECT q1 FROM table WHERE q1=2"));
$count1_3 = mysql_num_rows(mysql_query("SELECT q1 FROM table WHERE q1=3"));
$count1_4 = mysql_num_rows(mysql_query("SELECT q1 FROM table WHERE q1=4"));
$count1_5 = mysql_num_rows(mysql_query("SELECT q1 FROM table WHERE q1=5"));

$count2_1 = mysql_num_rows(mysql_query("SELECT q2 FROM table WHERE q2=1"));
$count2_2 = mysql_num_rows(mysql_query("SELECT q2 FROM table WHERE q2=2"));
$count2_3 = mysql_num_rows(mysql_query("SELECT q2 FROM table WHERE q2=3"));
$count2_4 = mysql_num_rows(mysql_query("SELECT q2 FROM table WHERE q2=4"));
$count2_5 = mysql_num_rows(mysql_query("SELECT q2 FROM table WHERE q2=5"));

$count3_1 = mysql_num_rows(mysql_query("SELECT q3 FROM table WHERE q3=1"));
$count3_2 = mysql_num_rows(mysql_query("SELECT q3 FROM table WHERE q3=2"));
$count3_3 = mysql_num_rows(mysql_query("SELECT q3 FROM table WHERE q3=3"));
$count3_4 = mysql_num_rows(mysql_query("SELECT q3 FROM table WHERE q3=4"));
$count3_5 = mysql_num_rows(mysql_query("SELECT q3 FROM table WHERE q3=5"));

$count4_1 = mysql_num_rows(mysql_query("SELECT q4 FROM table WHERE q4=1"));
$count4_2 = mysql_num_rows(mysql_query("SELECT q4 FROM table WHERE q4=2"));
$count4_3 = mysql_num_rows(mysql_query("SELECT q4 FROM table WHERE q4=3"));
$count4_4 = mysql_num_rows(mysql_query("SELECT q4 FROM table WHERE q4=4"));
$count4_5 = mysql_num_rows(mysql_query("SELECT q4 FROM table WHERE q4=5"));

$count5_1 = mysql_num_rows(mysql_query("SELECT q5 FROM table WHERE q5=1"));
$count5_2 = mysql_num_rows(mysql_query("SELECT q5 FROM table WHERE q5=2"));
$count5_3 = mysql_num_rows(mysql_query("SELECT q5 FROM table WHERE q5=3"));
$count5_4 = mysql_num_rows(mysql_query("SELECT q5 FROM table WHERE q5=4"));
$count5_5 = mysql_num_rows(mysql_query("SELECT q5 FROM table WHERE q5=5"));

$count6_1 = mysql_num_rows(mysql_query("SELECT q6 FROM table WHERE q6=1"));
$count6_2 = mysql_num_rows(mysql_query("SELECT q6 FROM table WHERE q6=2"));
$count6_3 = mysql_num_rows(mysql_query("SELECT q6 FROM table WHERE q6=3"));
$count6_4 = mysql_num_rows(mysql_query("SELECT q6 FROM table WHERE q6=4"));
$count6_5 = mysql_num_rows(mysql_query("SELECT q6 FROM table WHERE q6=5"));

$count7_1 = mysql_num_rows(mysql_query("SELECT q7 FROM table WHERE q7=1"));
$count7_2 = mysql_num_rows(mysql_query("SELECT q7 FROM table WHERE q7=2"));
$count7_3 = mysql_num_rows(mysql_query("SELECT q7 FROM table WHERE q7=3"));
$count7_4 = mysql_num_rows(mysql_query("SELECT q7 FROM table WHERE q7=4"));
$count7_5 = mysql_num_rows(mysql_query("SELECT q7 FROM table WHERE q7=5"));

$count8_1 = mysql_num_rows(mysql_query("SELECT q8 FROM table WHERE q8=1"));
$count8_2 = mysql_num_rows(mysql_query("SELECT q8 FROM table WHERE q8=2"));
$count8_3 = mysql_num_rows(mysql_query("SELECT q8 FROM table WHERE q8=3"));
$count8_4 = mysql_num_rows(mysql_query("SELECT q8 FROM table WHERE q8=4"));
$count8_5 = mysql_num_rows(mysql_query("SELECT q8 FROM table WHERE q8=5"));



echo "Q1_1 $count1_1 <br>";
echo "Q1_2 $count1_2 <br>";
echo "Q1_3 $count1_3 <br>";
echo "Q1_4 $count1_4 <br>";
echo "Q1_5 $count1_5 <br>";
echo "<hr />";
echo "Q2_1 $count2_1 <br>";
echo "Q2_2 $count2_2 <br>";
echo "Q2_3 $count2_3 <br>";
echo "Q2_4 $count2_4 <br>";
echo "Q2_5 $count2_5 <br>";
echo "<hr />";
echo "Q3_1 $count3_1 <br>";
echo "Q3_2 $count3_2 <br>";
echo "Q3_3 $count3_3 <br>";
echo "Q3_4 $count3_4 <br>";
echo "Q3_5 $count3_5 <br>";
echo "<hr />";
echo "Q4_1 $count4_1 <br>";
echo "Q4_2 $count4_2 <br>";
echo "Q4_3 $count4_3 <br>";
echo "Q4_4 $count4_4 <br>";
echo "Q4_5 $count4_5 <br>";
echo "<hr />";
echo "Q6_1 $count6_1 <br>";
echo "Q6_2 $count6_2 <br>";
echo "Q6_3 $count6_3 <br>";
echo "Q6_4 $count6_4 <br>";
echo "Q6_5 $count6_5 <br>";
echo "<hr />";
echo "Q7_1 $count7_1 <br>";
echo "Q7_2 $count7_2 <br>";
echo "Q7_3 $count7_3 <br>";
echo "Q7_4 $count7_4 <br>";
echo "Q7_5 $count7_5 <br>";
echo "<hr />";
echo "Q8_1 $count8_1 <br>";
echo "Q8_2 $count8_2 <br>";
echo "Q8_3 $count8_3 <br>";
echo "Q8_4 $count8_4 <br>";
echo "Q8_5 $count8_5 <br>";
echo "<hr />";
    ?>

正如您所看到的，这几乎是100行重复代码，最有可能做得更好。但是，我有点担心我能做到最好，并且很想听听你的想法。

Answer 1

咦？您应该使用数据库来实现此逻辑。在数据库中进行计数！

因此，您的前五个查询可以替换为：

SELECT SUM(q1 = 1) as q1, SUM(q1 = 2) as q2, SUM(q1 = 3) as q3,
       SUM(q1 = 4) as q4, SUM(q1 = 5) as q5
FROM table ;

或者，如果您愿意：

SELECT q1, COUNT(*) as cnt
FROM table
GROUP BY q1;

有没有办法使用较少的“mysql_num_rows”函数并获得相同的结果？

1 个答案: