Question

我正在尝试创建一个程序来查找整数数组中的最小整数。这是我的代码：

#include<iostream>

using namespace std;

int findMinimum(int array);

int findMinimum(int array){
  int arraySize = sizeof(array)/sizeof(int);
  int minimum = array[0];
  for (int i = 0; i < arraySize; i++){
    if (arraySize[i] < minimum){
      minimum = arraySize[i];
    }
  }
  return minimum;
}

int main(){
  int array[7] = {17,2,10,291,28,10,11};
  int minimum = findMinimum(array);
  cout << "The minimum of the array is: " << minimum;
}

我收到此错误：

    /Users/Danny/Desktop/C++/Practice/arrays.cpp:9:22: error: subscripted value is not an array, pointer, or vector
  int minimum = array[0];
                ~~~~~^~
/Users/Danny/Desktop/C++/Practice/arrays.cpp:11:18: error: subscripted value is not an array, pointer, or vector
    if (arraySize[i] < minimum){
        ~~~~~~~~~^~
/Users/Danny/Desktop/C++/Practice/arrays.cpp:12:26: error: subscripted value is not an array, pointer, or vector
      minimum = arraySize[i];
                ~~~~~~~~~^~
/Users/Danny/Desktop/C++/Practice/arrays.cpp:20:17: error: no matching function for call to 'findMinimum'
  int minimum = findMinimum(array);
                ^~~~~~~~~~~
/Users/Danny/Desktop/C++/Practice/arrays.cpp:7:5: note: candidate function not viable: no known conversion from 'int [7]' to 'int' for 1st argument
int findMinimum(int array){

如何解决这些错误？谢谢。

Answer 1

功能头应该是：

int findMinimum(int* array)

但是，对于int*，这不起作用：

int arraySize = sizeof(array)/sizeof(int);

因此你也应该将大小传递给函数：

int findMinimum(int* array, int size)

您还应该考虑使用std :: vector而不是数组。

Answer 2

这可能是作弊：

#include <algorithm>
#include <iostream>
#include <iterator>

int main() {
    int array[7] = { 17, 2, 10, 291, 28, 10, 11 };
    int min = *std::min_element(std::begin(array), std::end(array));
    std::cout << "The minimum of the array is: " << min << '\n';
    return 0;
}

Answer 3

你在这一行传递的内容

int minimum = findMinimum(array);

实际上是指向int数组的指针......实际上是指向第一个元素的指针。因此，您希望将功能签名更改为

int findMinimum(int* array)

在修改后的函数int findMinimum(int* array)中，下面的行将是错误的

int arraySize = sizeof(array)/sizeof(int);

因为array已经是分解指针了...所以你想再次将函数改为

int findMinimum(int* array, int size)

您的完整计划将是：

#include<iostream>

using namespace std;

int findMinimum(int* array, int arraySize);

int findMinimum(int* array, int arraySize){
  int minimum = array[0];
  for (int i = 0; i < arraySize; i++){
    if (arraySize[i] < minimum){
      minimum = arraySize[i];
    }
  }
  return minimum;
}

int main(){
  int array[7] = {17,2,10,291,28,10,11};
  int minimum = findMinimum(array, sizeof(array)/sizeof(int));
  cout << "The minimum of the array is: " << minimum;
}

整数数组C ++中的最小整数

3 个答案: