如何创建一个带有2个参数的boost :: function对象？

Question

我从老师那里得到了一个任务，我很难解决它。如何在一个带有一个参数的回调类型中发送一个带有2个参数的函数对象？我可以设法绑定一个带有一个参数的函数，但有两个它不仅改变占位符的数量并重新定义函数＆lt;＆gt;参数..

#include <functional>
#include <cstdlib>
#include <iostream>

using namespace std;
//definicija klase GLUT
class GLUT {
public:
typedef function<bool (unsigned char)> CallbackType;

  GLUT() : kbCallback(NULL) {}

  void setKeyboardCB(CallbackType cb) { 
    kbCallback = cb; 
  }
  void run();

private:
  CallbackType kbCallback;
};

void GLUT::run() {
  unsigned char c;   
  while (true) {
    if (kbCallback == NULL) {
      cout << "Nije definiran keyboard callback" << endl;
      break;
    }
    cin >> c;
    if (kbCallback(c) == false)
      break;
  }
}


class KbHandler 
{
public:
  KbHandler() {
  }
  bool Foo(unsigned char c, unsigned char compare) {
    if( c == compare )
      return false;
    cout << "Pritisnut " << c << '\n';
    return true;
  }
};

int main(int argc, char** argv) {

  GLUT glut; 
  typedef function<bool (unsigned char)> tip;
  using std::placeholders::_1;
  tip handler;

  KbHandler ob;

  handler2= std::bind( &KbHandler::foo,ob, _1); //<--he told me here

  glut.setKeyboardCB(handler2);
  glut.run();
  return 0;
}