Question

var array1 = {};

array1['one'] = new Array();
array1['one']['data'] = 'some text';
array1['one']['two'] = new Array();
array1['one']['two']['three'] = new Array();
array1['one']['two']['three']['data'] = 'some other text';

$.each(array1, function(key1, value1){
    $.each(value1['two']['three'], function(key1, value1){
        document.write('test');
    }
});

一切正常，除了它没有到达document.write。任何人都知道为什么？

Answer 1

请注意，Array（）替换是关键，缺少'）'

var array1 = {};

array1['one'] = new Object();
array1['one']['data'] = 'some text';
array1['one']['two'] = new Object();
array1['one']['two']['three'] = new Object();
array1['one']['two']['three']['data'] = 'some other text';

$.each(array1, function(key1, value1) {
    $.each(value1['two']['three'], function(key1, value1) {
        document.write('test');
    });
});

和写同样的东西的另一种方法:(写入引用你的对象的小tweek）

var array1 = {};

array1.one = new Object();
array1.one.data = 'some text';
array1.one.two = new Object();
array1.one.two.three = new Object();
array1.one.two.three.data = 'some other text';


$.each(array1, function(key1, value1) {
    $.each(value1['two']['three'], function(key1, value1) {
        document.write('test' + array1.one.data);
    });
});

最后，使用已弃用的新Object（）替换：

var array1 = {};

array1['one'] = {}
array1['one']['data'] = 'some text';
array1['one']['two'] = {};
array1['one']['two']['three'] = {};
array1['one']['two']['three']['data'] = 'some other text';

$.each(array1, function(key1, value1) {
    $.each(value1['two']['three'], function(key1, value1) {
        document.write('test');
    });
});

编辑：你的数组很有趣，为什么你可能会在对象声明中拥有字符串：

var array1 = {}; 
var fun="four"; 
array1.one = {}; 
array1.one.data = 'some text'; 
array1.one.two = {}; 
array1.one.two.three = {}; 
array1.one.two.three.data = 'some other text'; 
array1.one.two[fun] = {};
array1.one.two[fun].data=' howdy';

$.each(array1, function(key1, value1) { 
    $.each(value1.two.three, function(key1, value1) { 
        document.write('test'+array1.one.two[fun].data+ ":"+key1+":"+value1); 
    }); 
});

输出最后一个是：“测试你好：数据：其他一些文字”

Answer 2

document.write没有工作，因为你有一个语法错误，所以代码流永远不会到达它 - 你需要在each末尾的另一个括号，即

$.each(array1, function(key1, value1){
    $.each(value1['two']['three'], function(key1, value1){
        document.write('test');
    })
});

如果您要使用javascript进行任何非平凡的工作，我强烈建议您使用安装了Firebug的Firefox - 它的控制台会突出显示这些错误，否则如果您没有意识到这些错误就会失败，让你相信一切正常。

Answer 3

您在第二个)中错过each。

jquery.each多维数组

3 个答案: