080484b4 <main>:
80484b4: 55 push %ebp
80484b5: 89 e5 mov %esp,%ebp
80484b7: 57 push %edi
80484b8: 53 push %ebx
80484b9: 83 e4 f0 and $0xfffffff0,%esp
80484bc: 83 ec 40 sub $0x40,%esp
80484bf: 65 a1 14 00 00 00 mov %gs:0x14,%eax
80484c5: 89 44 24 3c mov %eax,0x3c(%esp)
80484c9: 31 c0 xor %eax,%eax
80484cb: c7 44 24 20 00 00 00 movl $0x0,0x20(%esp)
80484d2: 00
80484d3: b8 70 86 04 08 mov $0x8048670,%eax
80484d8: 89 04 24 mov %eax,(%esp)
80484db: e8 c0 fe ff ff call 80483a0 <printf@plt>
80484e0: b8 81 86 04 08 mov $0x8048681,%eax
80484e5: 8d 54 24 28 lea 0x28(%esp),%edx
80484e9: 89 54 24 04 mov %edx,0x4(%esp)
80484ed: 89 04 24 mov %eax,(%esp)
80484f0: e8 fb fe ff ff call 80483f0 <__isoc99_scanf@plt>
80484f5: c7 44 24 20 00 00 00 movl $0x0,0x20(%esp)
80484fc: 00
80484fd: eb 3f jmp 804853e <main+0x8a>
80484ff: 8b 44 24 20 mov 0x20(%esp),%eax
8048503: 05 20 a0 04 08 add $0x804a020,%eax
8048508: 0f b6 10 movzbl (%eax),%edx
804850b: 8b 44 24 20 mov 0x20(%esp),%eax
804850f: 31 d0 xor %edx,%eax
8048511: 88 44 24 27 mov %al,0x27(%esp)
8048515: 8d 44 24 28 lea 0x28(%esp),%eax
8048519: 03 44 24 20 add 0x20(%esp),%eax
804851d: 0f b6 00 movzbl (%eax),%eax
8048520: 3a 44 24 27 cmp 0x27(%esp),%al
8048524: 74 13 je 8048539 <main+0x85>
8048526: c7 04 24 84 86 04 08 movl $0x8048684,(%esp)
804852d: e8 8e fe ff ff call 80483c0 <puts@plt>
8048532: b8 01 00 00 00 mov $0x1,%eax
8048537: eb 41 jmp 804857a <main+0xc6>
8048539: 83 44 24 20 01 addl $0x1,0x20(%esp)
804853e: 8b 5c 24 20 mov 0x20(%esp),%ebx
8048542: b8 20 a0 04 08 mov $0x804a020,%eax
8048547: c7 44 24 1c ff ff ff movl $0xffffffff,0x1c(%esp)
804854e: ff
804854f: 89 c2 mov %eax,%edx
8048551: b8 00 00 00 00 mov $0x0,%eax
8048556: 8b 4c 24 1c mov 0x1c(%esp),%ecx
804855a: 89 d7 mov %edx,%edi
804855c: f2 ae repnz scas %es:(%edi),%al
804855e: 89 c8 mov %ecx,%eax
8048560: f7 d0 not %eax
8048562: 83 e8 01 sub $0x1,%eax
8048565: 39 c3 cmp %eax,%ebx
8048567: 72 96 jb 80484ff <main+0x4b>
8048569: c7 04 24 8b 86 04 08 movl $0x804868b,(%esp)
8048570: e8 4b fe ff ff call 80483c0 <puts@plt>
8048575: b8 00 00 00 00 mov $0x0,%eax
804857a: 8b 54 24 3c mov 0x3c(%esp),%edx
804857e: 65 33 15 14 00 00 00 xor %gs:0x14,%edx
8048585: 74 05 je 804858c <main+0xd8>
8048587: e8 24 fe ff ff call 80483b0 <__stack_chk_fail@plt>
804858c: 8d 65 f8 lea -0x8(%ebp),%esp
804858f: 5b pop %ebx
8048590: 5f pop %edi
8048591: 5d pop %ebp
8048592: c3 ret
However, when I try to see what is inside of 0x27(%esp) it just gives me in return a xor.
此外，％al的内容为十六进制65。 我不明白cmp在这里发生了什么。你有一个指令可以将另一条指令XOR与寄存器的值进行比较吗？结果是什么？
注意：0x414141是因为我插入了之前的scanf 3 A＆＃39;
