Question

在使用Google Places API时，我遇到了这段代码：

Place place = PlacePicker.getPlace(this, data);

这很好用。然而，在探索中，我遇到了一些我不了解的事情。地点是一个只有getter方法的界面。以下是接口Place的代码：

public interface Place extends Freezable<Place> {
    int TYPE_OTHER = 0;
    /* ... Similar type declarations */
    int TYPE_SYNTHETIC_GEOCODE = 1029;
    int TYPE_TRANSIT_STATION = 1030;

    String getId();

    List<Integer> getPlaceTypes();

    CharSequence getAddress();

    Locale getLocale();

    CharSequence getName();

    LatLng getLatLng();

    LatLngBounds getViewport();

    Uri getWebsiteUri();

    CharSequence getPhoneNumber();

    float getRating();

    int getPriceLevel();

    CharSequence getAttributions();
}

PlacePicker.getPlace（）的代码如下：

public class PlacePicker extends zza {
    public static final int RESULT_ERROR = 2;

    private PlacePicker() {
    }

    public static Place getPlace(Context context, Intent intent) {
        return zza.getPlace(context, intent);
    }

    /* Rest code of the class */
}

此处 zza 类的签名为protected abstract static class zza。

编辑：类 zza

的代码

abstract class zza {
    public static final int RESULT_ERROR = 2;

    zza() {
    }

    public static Place getPlace(Context context, Intent intent) {
        zzx.zzb(intent, "intent must not be null");
        zzx.zzb(context, "context must not be null");
        return (Place)zzc.zza(intent, "selected_place", PlaceImpl.CREATOR);
    }

    public static Status getStatus(Context context, Intent intent) {
        zzx.zzb(intent, "intent must not be null");
        zzx.zzb(context, "context must not be null");
        return (Status)zzc.zza(intent, "status", Status.CREATOR);
    }

    protected abstract static class zza {
        protected final Intent mIntent;

        public zza(String var1) {
            this.mIntent = new Intent(var1);
            this.mIntent.setPackage("com.google.android.gms");
        }

        protected Intent build(Activity activity) throws GooglePlayServicesRepairableException, GooglePlayServicesNotAvailableException {
            Theme var2 = activity.getTheme();
            TypedValue var3 = new TypedValue();
            TypedValue var4 = new TypedValue();
            if(var2.resolveAttribute(16843827, var3, true) && !this.mIntent.hasExtra("primary_color")) {
                this.mIntent.putExtra("primary_color", var3.data);
            }

            if(var2.resolveAttribute(16843828, var4, true) && !this.mIntent.hasExtra("primary_color_dark")) {
                this.mIntent.putExtra("primary_color_dark", var4.data);
            }

            GoogleApiAvailability.getInstance().zzak(activity);
            return this.mIntent;
        }
    }
}

现在我的问题是，当所有类都没有实现Place接口时，place.getName()如何工作？编写方法定义到底在哪里？

可以直接使用接口对象吗？

0 个答案: