Question

您好我一直在开发一个C ++银行应用程序，该应用程序应该能够拥有多个相关字段的帐户。我遇到了一些问题：

在Display或ShowInfo函数中显示帐户信息时，名字的第一个字母和中间的首字母不会显示。
创建帐户时，只能搜索最近的帐户并在显示数据中显示。我知道需要一个数组来实现这一点，我只是不确定是否正确实现了这一点。

感谢您的帮助。任何意见都表示赞赏！

#include <stdlib.h>
#include <conio.h>
#include <iostream>
#include <string>

using namespace std;

class BankAccount{
    double Balance = 0.0;
    char ans;
    public:struct Name{
        char Last_Name[50];
        char First_Name[50];
        char Middle_Initial[5];
    }Name;
    public:struct Account{
        char Type[1];
        int Account_Number;
    }Account;
    public:
    void CreateAccount();
    void Withdraw();
    void Deposit();
    void Display();
    void ShowInfo();
    int Menu();

};

void BankAccount::CreateAccount(){
    do
    {
        cout << "\nEnter account number: ";
        cin >> Account.Account_Number;
        cout << "\nEnter the last name for the account: ";
        cin.ignore();
        cin.getline(Name.Last_Name, 50);
        cout << "\nEnter the first name for the account: ";
        cin.ignore();
        cin.getline(Name.First_Name, 50);
        cout << "\nEnter the Middle initial for the account: ";
        cin.ignore();
        cin.getline(Name.Middle_Initial, 5);
        cout << "\nEnter the type of account (C/S) : ";
        cin >> Account.Type;
        cout << "\nEnter the initial balance of the account: ";
        cin >> Balance;
        cout << "\n\nAccount Created.";
        cout << "\n\nCreate new account? (Y/N) : ";
        cin >> ans;

        while (ans != 'Y' && ans != 'N'){
            cout << "Invalid input. Create new account? (Y/N) : ";
            cin >> ans;
        }
        cout << endl;
    } while (ans != 'N');
};
void BankAccount::Withdraw(){
    int actNum;
    double amount;
    cout << "Enter the account number for the account that you wish to withdraw funds: ";
    cin >> actNum;
    if (actNum == Account.Account_Number){
        cout << "Enter the amount you would like to withdraw: ";
        cin >> amount;
        Balance = Balance - amount;
    }
    else if (actNum != Account.Account_Number){
        cout << "No account found under that number! Try again!";
    }

}
void BankAccount::Deposit(){
    int actNum;
    double amount;
    cout << "Enter the account number for the account that you wish to deposit funds: ";
    cin >> actNum;
    if (actNum == Account.Account_Number){
        cout << "Enter the amount you would like to deposit: ";
        cin >> amount;
        Balance = Balance + amount;
    }
    else if (actNum != Account.Account_Number){
        cout << "No account found under that number! Try again!";
    }
}
void BankAccount::Display(){
    int actNum;
    cout << "Enter the account number for the account that you wish to display account information for: ";
    cin >> actNum;
    if (actNum == Account.Account_Number){
        cout << "Account details for " << Name.First_Name << " " << Name.Middle_Initial << " " << Name.Last_Name << "'s account: " << endl;
        cout << "Account Number: " << Account.Account_Number << endl;
        cout << "Account Type (Checking / Savings): " << Account.Type << endl;
        cout << "Account Balance:  $" << Balance << endl;
    }
    else if (actNum != Account.Account_Number){
        cout << "No account found under that number! Try again!";
    }

}
void BankAccount::ShowInfo(){
    cout << "Account details for " << Name.First_Name << " " << Name.Middle_Initial << " " << Name.Last_Name << "'s account: " << endl;
    cout << "Account Number: " << Account.Account_Number << endl;
    cout << "Account Type (Checking / Savings): " << Account.Type << endl;
    cout << "Account Balance:  $" << Balance << endl;    

}

int main(int argc, char *argv){
    BankAccount ob;
    char ch;

    cout << "Welcome to Console Banking Application V 1.0!";
    cout << "\nSelect an item from the list below by entering the corresponding letter.";
    do{
        cout << "\n\n A. Create Account \n B. Withdraw \n C. Deposit \n D. Show Account Details \n\n Q. Exit Application\n\n";
        ch = ob.Menu();
        switch (ch){
        case 'A':
        case 'a': ob.CreateAccount();
            ob.ShowInfo();
            break;
        case 'B': 
        case 'b': ob.Withdraw();
            break;
        case 'C':
        case 'c': ob.Deposit();
            break;
        case 'D':
        case 'd': ob.Display();
            break;
        case 'Q':
        case 'q': ob.ShowInfo();
                  exit(1);
            break;
        }

    } while (1);
}
int BankAccount::Menu(){
    char ch;
    cout << "Select an option: ";
    cin >> ch;
    return ch;
}

Answer 1

简单的答案是：您只有一个银行帐户。

如果您查看主要功能，则可以创建一个，只有一个 BankAccount。正如您可能猜到的，一个BankAccount不能用于代表多个BankAccounts（SoAs除外）。

因此，您需要BankAccounts的数组。它是这样的：

BankAccount obs[10];

现在你有10个BankAccounts，没有更多。因此，每次要创建新的BankAccount时，只需确保在当前未使用的数组中的BankAccount上创建它。

obs[0].CreateAccount();
obs[0].ShowInfo();
obs[0].Deposit();
//Make a new account
obs[1].CreateAccount();
...

为了更进一步，让我们考虑一下你有10个BankAccounts，只有10个。这个现在不是很广泛吗？什么是只有10个账户的银行？可能在适当的时候停业。

天真的解决方案是添加更多。 50,100甚至1000.但你真的想回去每次都更新这个号码吗？这太乏味了。

幸运的是，我们可以使用一个方便的容器：

#include <vector>
...
std::vector<BankAccount> obs;
...

这基本上是一个在需要时自动扩展的数组。我不会详细介绍如何使用向量，因为我相信你可以自己轻松学会这样做。但是，我会告诉你这个link，所以你知道你可以从哪里开始。

没有多个帐户的C ++ Banking应用程序

1 个答案: