Question

我正在使用json数据处理android应用程序。为此，我使用php和json制作了webservices。我得到了结果，但它不适合我的应用程序。以下是我的代码：

<?php
require("config.inc.php");
$query= "SELECT * from zone";
try {
$stmt   = $db->prepare($query);
$result = @$stmt->execute($query_params);   
}
catch (PDOException $ex) {
$zone["success"] = 0;
$zone["message"] = "Database Error!";
die(json_encode($zone));
}
$rows = $stmt->fetchAll();
if ($rows) {

$zone["posts"]   = array();

foreach ($rows as $row) {
    $post  = array();
    $post["zone_id"]=$row["zone_id"];
    $post["zone_name"]=$row["zone_name"];
    $post["zone_turn"]=$row["zone_turn"];
    $post["zone_charge"]=$row["zone_charge"];

    $query1= "SELECT * from pincode_master where zone_id=".$row['zone_id']."";
    try {
        $stmt   = $db->prepare($query1);
        $result = @$stmt->execute($query_params);   
    }
    catch (PDOException $ex) {
        $zone["success"] = 0;
        $zone["message"] = "Database Error!";
        die(json_encode($zone));
    }
    $rows1 = $stmt->fetchAll();
    if ($rows1) {
        $zone["posts1"]   = array();

        foreach ($rows1 as $row1) {
            $post1  = array();
            //$post1["zone_id"]=$row1["zone_id"];
            $post1["pincode_number"]=$row1["pincode_number"];
            //echo $post["pincode_number"];

             array_push($zone["posts1"], $post1);
        }

    }
     array_push($zone["posts"], $post,$zone["posts1"]);
    }  
  echo json_encode($zone);
  } else {
  $zone["success"] = 0;
  $zone["message"] = "No Zone asssign for this day!";
  }
 ?>

从上面的代码我得到了json数组。除了pincode编号之外，它将包含一个数组中的所有数据，因为我是从另一个表中得到的。：

{"posts[{"zone_id":"2","zone_name":"A","zone_turn":"Monday,Thrusday","zone_charge":"15"},[{"pincode_number":"390007"},{"pincode_number":"390016"},{"pincode_number":"390021"},{"pincode_number":"390023"}],{"zone_id":"3","zone_name":"B","zone_turn":"Tuesday,Friday","zone_charge":"15"},[{"pincode_number":"390001"},{"pincode_number":"390004"},{"pincode_number":"390006"},{"pincode_number":"390010"},{"pincode_number":"390018"},{"pincode_number":"390019"},{"pincode_number":"390020"},{"pincode_number":"390022"}],{"zone_id":"7","zone_name":"W","zone_turn":"Saturday,Sunday,Friday","zone_charge":"15"},[{"pincode_number":"390001"},{"pincode_number":"390004"},{"pincode_number":"390006"},{"pincode_number":"390010"},{"pincode_number":"390018"},{"pincode_number":"390019"},{"pincode_number":"390020"},{"pincode_number":"390022"}],{"zone_id":"8","zone_name":"X","zone_turn":"Wednesday,Saturday,Sunday","zone_charge":"15"},[{"pincode_number":"390001"},{"pincode_number":"390004"},{"pincode_number":"390006"},{"pincode_number":"390010"},{"pincode_number":"390018"},{"pincode_number":"390019"},{"pincode_number":"390020"},{"pincode_number":"390022"}]],"posts1":[{"pincode_number":"390001"},{"pincode_number":"390004"},{"pincode_number":"390006"},{"pincode_number":"390010"},{"pincode_number":"390018"},{"pincode_number":"390019"},{"pincode_number":"390020"},{"pincode_number":"390022"}]}

但我想要下面一个：

{"posts[{"zone_id":"2","zone_name":"A","zone_turn":"Monday,Thrusday","zone_charge":"15","pincode_number":{"390007","390016","390021"}}]}

Answer 1

您不必创建像这样的新数组$zone["posts1"] = array();来添加您的密码，您只需将密码数据附加到您现有的$ post数组中。

$post  = array();
$post["zone_id"]=$row["zone_id"];
$post["zone_name"]=$row["zone_name"];
$post["zone_turn"]=$row["zone_turn"];
$post["zone_charge"]=$row["zone_charge"];
.
.
.

$rows1 = $stmt->fetchAll();
    if ($rows1) {

        foreach ($rows1 as $row1) {

            $post["pincode_number"][] = $row1["pincode_number"];

        }

    }
    array_push($zone["posts"], $post);
   }

Answer 2

只需将$post1设为多维数组，然后在foreach之后使用array_push。如下所示：

    foreach ($rows1 as $row1) {
        $post1  = array();
        $post1["pincode_number"][] = $row1["pincode_number"];

    }
    array_push($zone["posts1"], $post1);

如何在php中的另一个json数组中创建一个json数组

2 个答案: