Question

我正在尝试创建一个视图，该视图将返回3个级别的数据字符串。

select bf.functionName + ' \ ' + ISNULL(bf1.functionName + ' \ ', '') + ISNULL(bf2.functionName, '') from tblBusinessFunction bf
inner join tblBusinessFunction bf1 on bf1.parentID = bf.id and bf.level = 0
inner join tblBusinessFunction bf2 on bf2.parentID = bf1.id and bf1.level = 1

以上仅返回顶级祖父母和父母而非子级别。

这就是表格的样子

| id   | functionName                | parentID |  level  |
|:-----|----------------------------:|:--------:|:-------:|
| 101  | Portfolio Strategy Functions|   NULL   |    0    |
| 110  | Research                    |   101    |    1    |
| 111  | Economic Forecasting        |   110    |    2    |

现在我的查询将返回Portfolio Strategy Functions \ Research \ Economic Forecasting，但我希望它也返回Portfolio Strategy Functions \ Research，但它不会做。{/ p>

Answer 1

我试图解决

declare @T table ( id int, functionName varchar(50), parentid int, level int )

insert @T 
values 
(101,'Portfolio Strategy Functions',null,0),
(110,'Research',101,1),
(111,'Economic Forecasting',110,2)

;with Outline as
( select id,level,functionName = convert(varchar(max),functionName) from @T where level = 0 
  union all 
  select T.ID, T.level, functionName = O.functionName +' / '+ T.functionName from @T T
  join Outline O on O.id = T.parentid
)

select * from OutLine
where level > 0

这是结果

(3 row(s) affected)
id          level       functionName
----------- ----------- ----------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------
110         1           Portfolio Strategy Functions / Research
111         2           Portfolio Strategy Functions / Research / Economic Forecasting

(2 row(s) affected)

sql - 显示祖父母，父母和孩子

1 个答案: