Question

下面的代码在字典中搜索单词，并在 search.html 上呈现结果，因此我需要在该页面上对结果进行分页，我该怎么做？我在这里阅读了＃{3}}，但我不知道如何将分页代码嵌入到我的代码中。

def search(request):
    if 'results' in request.GET and request.GET['results']:
        results = request.GET['results']
        word = words.objects.filter(title__icontains = results).order_by('title')
        return render_to_response('myapp/search.html',
        {'word': word, 'query': results })
    else:
        return render(request, 'myapp/search.html')

Answer 1

from django.core.paginator import Paginator

def search(request):
    if 'results' in request.GET and request.GET['results']:
        page = request.GET.get('page', 1)

        results = request.GET['results']
        word = words.objects.filter(title__icontains = results).order_by('title')
        paginator = Paginator(word, 25) # Show 25 contacts per page
        word = paginator.page(page)
        return render_to_response('myapp/search.html',
                 {'word': word, 'query': results })
    else:
        return render(request, 'myapp/search.html')

Answer 2

当我需要对查询数据进行分页并覆盖query_set函数时，我更喜欢使用ListView类。像这样......

class FoodMenuView(generic.ListView):
    paginate_by = 10 #use your paginated  value here
    template_name = 'order/_food_menu.html' # your own template
    context_object_name = "list_of_food"

    def get_queryset(self):
        return Food.objects.filter(price=request.GET['price'])

如何在Django中对搜索结果进行分页？

2 个答案: