在每3个字符串后用空格替换逗号

Question

我有一个csv文件，如下所示：

"user1","track1","player1","user1","track2","player2","user1","track3","player3",........

我需要做的是用空格（不是所有的逗号）替换逗号，只删除playerIds之后的逗号（指定一行，以便稍后将它们导入Mysql）。所以，我需要结果如下：

"user1","track1","player1" "user1","track2","player2" "user1","track3","player3" ........

我发现我们可以用空格sed替换逗号：

sed 's/,/ /g' output.csv >output2.csv

然而，它用空格替换所有逗号..我不知道如何在每3个字符串后才能这样做。任何的想法？

谢谢，

Answer 1

您可以像这样使用sed：

sed -E 's/(([^,]*,){2}[^,]*),/\1 /g' file

"user1","track1","player1" "user1","track2","player2" "user1","track3","player3"