Question

| id | user  | team   | month | result |
|----|-------|--------|-------|--------|
| 1  | Joe   | red    | sept  | 100    |
| 2  | Joe   | red    | oct   | 40     |
| 3  | Jim   | red    | sept  | 70     |
| 4  | Jim   | red    | oct   | 50     |
| 5  | Susy  | red    | sept  | 40     |
| 6  | Tim   | blue   | sept  | 60     |
| 7  | Tim   | blue   | oct   | 100    |
| 8  | Betty | blue   | sept  | 70     |
| 9  | Dave  | blue   | sept  | 20     |
| 10 | Stan  | green  | oct   | 40     |
| 11 | Alan  | green  | sept  | 80     |
| 12 | Tina  | green  | oct   | 100    |
| 13 | Tina  | green  | sept  | 30     |
| 14 | Rick  | yellow | oct   | 50     |
| 15 | Ellen | yellow | oct   | 60     |

这可能。

我需要获得每个团队最多2个用户，并获得最佳结果。

例如，以下结果是每支球队得分最高的2位球员：

| 1  | Joe   | red    | sept  | 100    |
| 3  | Jim   | red    | sept  | 70     |
| 7  | Tim   | blue   | oct   | 100    |
| 8  | Betty | blue   | sept  | 70     |
| 12 | Tina  | green  | oct   | 100    |
| 11 | Alan  | green  | sept  | 80     |
| 15 | Ellen | yellow | oct   | 60     |
| 14 | Rick  | yellow | oct   | 50     |

或者是使用多个查询执行此操作的唯一方法吗？

Answer 1

你可以这样做：

SELECT * FROM 
    (SELECT t.id,t.team,count(*) as rnk
    FROM YourTable t
    INNER JOIN YourTable s
     ON(t.id = s.id and t.team = s.team and t.result >= s.result))x
WHERE rnk <= 2

Answer 2

您可以尝试以下操作：

select t.*
from `tbl` t
where ( select count(*)
        from `tbl`
        where `team` = t.`team` and `result` >= t.`result` ) < 3

SQLFiddle

每个团队最多可获得2个用户，结果最佳MYSQL

2 个答案: