我目前正在尝试为一个单项目的文本文件制作竞赛记分牌。
每个参赛者都有一个competitor_no，competitor_name和3个分数，它们都显示在文本文件的不同行中（因此每个参赛者的数据需要5行），例如：
1
Eliza Ianson
9.19
11.79
21.66
2
Cece Durant
17.03
7.02
17.72
我需要能够添加3个分数才能获得总分。我有50个竞争对手，需要将它们全部进行比较，以显示打印竞争对手数量，名称和总分的前3名竞争对手。有没有办法将行值赋给变量？
显然，我需要一次比较5行，以获得每个竞争对手所需的信息，并处理数据，这就是我在程序中设置代码的方式。
file = open('veggies_2014.dat')
for line in file:
first_place = []
second_place = []
third_place = []
a = 1
b = 2
c = 3
d = 4
e = 5
if line == a:
competitor_no = line
elif line == b:
competitor_name = line
elif line == c:
cucumber = line
elif line == d:
carrot = line
elif line == e:
runner_bean = line
a += 5
b += 5
c += 5
d += 5
e += 5
score = float(cucumber) + float(carrot) + float(runner_bean)
print(score)
if score > first:
first = score
first_place.append(competitor_no)
first_place.append(competitor_name)
first_place.append(score)
elif score > second:
second = score
second_place.append(competitor_no)
second_place.append(competitor_name)
second_place.append(score)
elif score > third:
third = score
third_place.append(competitor_no)
third_place.append(competitor_name)
third_place.append(score)
file.close()
print (first_place)
print (second_place)
print (third_place)
当我正在处理包含数字的文件时，我可以获得得分if语句，但必须包含该名称是我似乎绊脚的地方。
有什么建议吗？
答案 0 :(得分：0)
你可以做这样的事情（没有经过测试 - 但你明白了）： 基本上，每次计数到0时，你都会将得分保存在personDict中，并将该人的姓名作为关键....
count = 0
c1_no = None;
personDict = dict()
with open("veggies_2014.dat") as f:
score = 0
for line in f:
if count%5==0:
if c1_no:
personDict[c1_no] = score
c1_no = line
score = 0
elif count%5 == 1:
c1_name = line
elif count%5 in (2,3,4):
score += float(line)
count += 1
#now do whatever you want with the personDict..you will have something like {Emily:10} assuming Emily's scores were 2,3,5 etc
答案 1 :(得分：0)
以下是我提出的建议：
file_content = '''1
Eliza Ianson
9.19
11.79
21.66
2
Cece Durant
17.03
7.02
17.72
3
Foo Bar
10
9.5
11.2
4
Superman
7.9
12.15
9.75
'''
def chunks(l, n):
"""Yield successive n-sized chunks from l."""
""" from http://stackoverflow.com/questions/312443/how-do-you-split-a-list-into-evenly-sized-chunks-in-python """
for i in xrange(0, len(l), n):
yield l[i:i+n]
users = []
for user_data in chunks(file_content.splitlines(), 5):
user_id = int(user_data[0])
user_name = user_data[1]
scores = list(map(float, user_data[2:]))
overall_score = sum(scores)
users.append(dict(
user_id=user_id,
user_name=user_name,
scores=scores,
overall_score=overall_score
))
top_3 = sorted(users, key=lambda x: x['overall_score'], reverse=True)[:3]
答案 2 :(得分：0)
由于您知道信息在文件中的显示顺序，因此请尝试一次以五行为单位读取文件，然后相应地处理。在下面的实现中，我将信息存储在2D列表中，然后按分数排序，从而获得最高分。
data = []
count = 1
with open("veggies_2014.dat") as f:
line = f.readline()
while line and int(line) == count:
score = 0
entry = []
entry.append(f.readline()) #read line with c_name
for i in range(3):
score += float(f.readline()) #add scores
entry.append(score)
data.append(entry)
line = f.readline()
count += 1
print(data)
data = sorted(data, key = lambda l:l[1], reverse = True)
print()
print(data)
答案 3 :(得分：0)
我在一些答案的帮助下使用了完成的代码。虽然我选择在我的应用程序中将它分成不同的功能，但部分可以重复使用。
data = []
count = 1
print("")
print("For 2014 Results please enter: veggies_2014.txt ")
print("For 2015 Results please enter: veggies_2015.txt")
print("For 2016 Results please enter: veggies_2016.txt ")
fname = raw_input("Enter file name: ")
with open(fname) as f:
line = f.readline()
while line and float(line) == count:
score = 0
entry = []
entry.append(count)
entry.append(f.readline().strip())
for i in range(3):
score += float(f.readline()) #add scores
score = round(score, 2)
entry.append(score)
data.append(entry)
line = f.readline()
count += 1
data = sorted(data, key = lambda l:l[2], reverse = True)
print("")
final=[]
for line in data:
for i in line:
final.append(i)
我添加了此代码以更清晰地显示记分板。
a=0
b=3
x=1
for i in range(0,3):
place=[]
place = final[a:b]
string = " ".join(str(x) for x in place)
print (str(x) + ". " + string)
a += 3
b += 3
x += 1
print("")