Question

我在一次小挑战中遇到了一些麻烦。我试图检查是否在数组中找到字符串的字符，如果是，请停止循环，记录该值，然后重新开始使用新的字符串字符。谁能elp

function LetterChanges(str) {    
    var alphabet =   ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"];
    // code goes here
    var myString = "";
    for(var i = 0; i <= myString.length; i++) {
        for(var o = 0; o < 25; o++){
            var getChar = myString += str.charAt(i)
            if (getChar == alphabet[o]){
                alert(getChar);
                break;
            }
        }
    }
    alert(getChar);          
}

// keep this function call here
LetterChanges("Test");`

Answer 1

function LetterChanges(str) {
    // code goes here
    var regex=/[abcdefghijklmnopqrstuvwxyz]/;

    // simply you can give as below
    regex = /[a-z]/;

    //if you want to match Cap A-Z too make the regex to ignore case as below
    // regex = /[a-z]/i; 

    var myString = "";
    for (var i = 0; i < str.length; i++) {
        var char = str[i];
        if (regex.test(char)) {
            myString += char;
            console.log(myString)
        }
    }
    console.log(myString);
}

// keep this function call here
LetterChanges("Test");

Answer 2

如果您刚刚开始，请查看如何使用debugger和断点。他们会帮助您弄清楚您的代码在做什么。
尝试循环alphabet.length而不是25
创建var getChar似乎没必要。试着做if(str.chartAt(i) == alphabet[o])

Answer 3

function LetterChanges(str) {    
    var alphabet =   ["a","b","c","d","e","f","g","h","i","j","k","l","m","n","o","p","q","r","s","t","u","v","w","x","y","z"];
    
   
    for(var i = 0; i <= str.length; i++) {
        for(var o = 0; o < 25; o++){
              
            if (str.charAt(i) == alphabet[o]){
                alert(getChar);
                break;
            }
        }
    }
    alert(getChar);          
}

// keep this function call here
LetterChanges("Test"); </script>

请注意，字母'T'在数组中不匹配。所以只有'e'，'s'，'t'会警惕。

检查字符串字符是否与数组值匹配

3 个答案: