Question

我正在制作Rock Papper Scisors游戏，我面临的问题是我需要根据最佳3,5或7来设置胜利者，并且这样做我需要计算我的投注表很简单的连续查询数：

BO3

ID|GAME_ID|WINNER
1 |145    |15
2 |145    |14
3 |145    |15
4 |145    |15

15需要赢，我怎么能在mysql中计算它？

例如：

GAME_ID|WINNER|CONSECUTIVES
    145|15    |2

非常感谢。

Answer 1

我认为你需要变量：

select gameid, winner, max(rn)
from (select s.*,
             (@rn := if(@gw = concat_ws(':', gameid, winner), @rn + 1,
                        if(@gw := concat_ws(':', gameid, winner), 1, 1)
                       )
             ) as rn
      from scores s cross join
           (select @gw := '', @rn := 0) params
      order by s.id
     ) s
group by gameid, winner;

Here是一个SQL小提琴。

Answer 2

也许是这样的：

select y.winner, 
  case when y2.cnt <= 3 then 'Best of 3' 
       when y2.cnt <= 5 then 'Best of 5' 
       when y2.cnt <= 7 then 'Best of 7' 
   end, count(*)
from yourtable y join (
  select count(*) cnt, gameid
  from yourtable
  group by gameid) y2 on y.gameid = y2.gameid
group by y.gameid, y.winner, y2.cnt
having count(*) = 2 and y2.cnt <= 3 or 
 count(*) = 3 and y2.cnt <= 5 or 
 count(*) = 4 and y2.cnt <= 7

SQL Fiddle Demo

得到连续的行mysql

2 个答案: