Question

我在codeigniter中连接两个表时遇到此错误。

Error Number: 1064

You have an error in your SQL syntax; check the manual that
corresponds to your MariaDB server version for the right syntax to use
near '.`id = a`.`assignee_key where a`.`assigned_to="office" and
user`.`id="53"`' at line 1

select a`.* from address as `a LEFT JOIN user ON user`.`id = a`.`assignee_key where a`.`assigned_to="office" and user`.`id="53"

$this->db->select('select a.* from address as a LEFT JOIN  user  ON  user.id = a.assignee_key where a.assigned_to="office" and user.id="'.$user_id.'"');
$query = $this->db->get();
return $query->row();

Answer 1

别名表名称有问题。试试这个

$this->db->select('select a.* from address a LEFT JOIN user u ON u.id = a.assignee_key where a.assigned_to="office" and u.id="'.$user_id.'"');
$query = $this->db->get();
return $query->row();

Answer 2

你有两个选择。以下是查询的更好/结构化版本。

$this->db->select("a.*")
             ->from("address as a")
             ->join("user","user.id = a.assignee_key","left")
             ->where(array("a.assigned_to"=>"office","user.id"=>$user_id));         
    $query = $this->db->get(); 
    return $query->row();

更新：对于评论，请尝试左外连接

->join("user","user.id = a.assignee_key","left outer")

它保留第一个（左）表中不匹配的行，将它们与第二个（右）表形状的NULL行连接。

错误号码：1064

2 个答案: