Question

在下面的查询中，我使用Subquery1和Subquery2来获取帐号和帐户名。但是，除了子查询2中的附加表account_nameinfo_t之外，第一个子查询和第二个子表连接相同的表以获取帐户名。有没有办法我避免从其他表中选择并只使用子查询1的值，即帐号＃来获取子查询2中的帐户名称？

SELECT 
       (
        SELECT acct.account_no
         FROM group_t grp1, account_t acct
        WHERE     grp1.poid_id0 = grpbm.obj_id0
              AND acct.poid_id0 = grp1.ACCOUNT_OBJ_ID0
       )  PARENT_ACCOUNT, -- (#Subquery 1 to get the parent account)
       (
        SELECT ant.Firstname || ' ' || ant.LastName
         FROM group_t grp1, account_t acct,account_nameinfo_t ant
        WHERE     grp1.poid_id0 = grpbm.obj_id0
              AND acct.poid_id0 = grp1.ACCOUNT_OBJ_ID0
              AND ant.obj_id0 = acct.poid_id0
       ) "ACCOUNT NAME", -- (#Subquery 2 to get the parent account name which is in a different table)
       bgs.REC_ID2 RECORD_TYPE,
       bgs.current_bal VALUE
 FROM group_t grp,
      group_billing_members_t grpbm,
      BAL_GRP_SUB_BALS_T bgs
WHERE     poid_type = '/group/sharing/discounts'
      AND grpbm.OBJECT_ID0 = grp.ACCOUNT_OBJ_ID0
      AND bgs.obj_id0 = grp.BAL_GRP_OBJ_ID0
      AND bgs.rec_id2 NOT IN (1000203,
                              1030001,
                              1000303,
                              1000306)
ORDER BY PARENT_ACCOUNT;

Answer 1

Oracle支持您可能认为有用的WITH子句：http://psoug.org/reference/with.html

基本上，它允许您在查询中创建可以多次访问的临时视图。在您的情况下，您的公共连接的结果可以“分解”，结果可以重复使用。

Answer 2

正如ALEXPOOL建议的那样，我尝试使用ANSI连接并且它可以工作。欢迎任何好处。

SELECT C1."PARENT ACCOUNT",C1."ACCOUNT NAME", A1.RECORD_TYPE, A1.CURRENT_BAL
FROM 
    (SELECT  
      bgs.REC_ID2 RECORD_TYPE,
      bgs.current_bal,grpbm.OBJ_ID0
    FROM  group_t grp ,
          group_billing_members_t grpbm,
          BAL_GRP_SUB_BALS_T bgs
        WHERE
        poid_type='/group/sharing/discounts'   and
      grpbm.OBJECT_ID0 = grp.ACCOUNT_OBJ_ID0 and
      bgs.obj_id0 = grp.BAL_GRP_OBJ_ID0      and
      bgs.rec_id2 not in (                    1000203,
                        1030001,
                            1000303,
                            1000306) ) A1 JOIN

  ( SELECT grp1.ACCOUNT_OBJ_ID0,grp1.POID_ID0
     FROM group_t grp1
  )  B1 ON (B1.poid_id0 = A1.OBJ_ID0)
  JOIN 
  ( SELECT acct.account_no "PARENT ACCOUNT",
            ant.FIRST_NAME||' '||ant.LAST_NAME "ACCOUNT NAME",
            acct.poid_id0 
     FROM 
        account_t acct,
        account_nameinfo_t ant  
        WHERE acct.poid_id0 = ant.obj_id0 and 
              ant.rec_id=1) C1 ON (C1.poid_id0 = B1.ACCOUNT_OBJ_ID0)
  order by C1."PARENT ACCOUNT";

Answer 3

看起来您可以使用简单连接而不是子查询来简化此操作，无论是在选择列表中还是作为内联视图：

// Special case for the head.
if (elementToDelete == *head) {
    *head = element->next;
    free(elementToDelete);
    return true;
}

您似乎只在SELECT acct.account_no AS "PARENT ACCOUNT", ant.first_name||' '||ant.last_name AS "ACCOUNT NAME", bgs.rec_id2 AS record_type, bgs.current_bal FROM group_t grp JOIN group_billing_members_t grpbm ON grpbm.obj_id0 = grp.account_obj_id0 JOIN group_t grp1 ON grp1.poid_id0 = grpbm.obj_id0 JOIN bal_grp_sub_bals_t bgs ON bgs.obj_id0 = grp.bal_grp_obj_id0 JOIN account_t acct ON acct.poid_id0 = grp1.account_obj_id0 JOIN account_nameinfo_t ant ON ant.obj_id0 = acct.poid_id0 WHERE grp.poid_type='/group/sharing/discounts' AND bgs.rec_id2 not in (1000203, 1030001, 1000303, 1000306) AND ant.rec_id = 1 ORDER BY "PARENT ACCOUNT";的两个引用之间使用group_billing_members_t，并且不清楚它们是否都指向同一记录，或者是否扩展为多行。列名似乎有些不一致，这可能来自您重新输入代码而不是复制和粘贴代码。如果它是相同的记录，那么您似乎能够删除该表并重新加入：

group_t

没有表格结构，关系，样本数据和预期结果，但相当推测。

Oracle SQL子查询标量作为其他子查询的输入

3 个答案: