我的按钮打印得很笨拙

时间:2016-03-08 06:16:33

标签: html css

  1. 我有一张表,我在每行的末尾打印一个按钮。我希望这个按钮很小。

  2. 尽管使用溢出省略号,但在打印表格时,我的文本不会被截断。我不想要水平滚动条。

  3. 我的表格标题栏,当我向下滚动时,最上面一行总是隐藏。

  4. img

    非常感谢任何帮助。这是我的 CSS 脚本https://jsfiddle.net/v6sahfyc/1/

    编辑:在这里添加php代码:

    // <?php   
        // echo "<div id='awesometable'>"; 
    // ?>
    
    <!-- <CAPTION>RESERVATION TABLE</CAPTION> -->
    <?php   
    
        echo "<br><br><p style=\"font-family:verdana; font-size:100%; margin-left: 5em;\"><i><strong>Reservation Table.</strong></i></p>";
        echo "<table id='reservation' class='inlineTable'>";  //style='border: solid 1px black;'
        //echo "<thead>";
        echo "<tr>";
        echo "<th class=\"row-1 uid\">UserId</th>";
        echo "<th class=\"row-2 rname\">Resource <br> Name</th>";
        echo "<th class=\"row-3 rtype\">Resource <br> Type</th>";
        echo "<th class=\"row-4 rloc\">Resource <br> Location</th>";
        echo "<th class=\"row-5 treq\">Time <br> Required </th>";
        echo "<th class=\"row-6 REM\">Delete? </th>";
        echo "</tr>";
        //echo "</thead>\n";            
        //echo "<col = width: 3em />";
    ?>
    <?php
        $username = "root";
        $password = "";
        $host = "localhost";
    
        $connector = mysql_connect($host,$username,$password) or die("Unable to connect");
        $selected = mysql_select_db("mydb", $connector) or die("Unable to connect");
        $selectSQL = "SELECT  user_ID, ResourceName, ResourceType, ResourceLocation, ReservationTime FROM reservation_table";
        if( !( $selectRes = mysql_query( $selectSQL ) ) ){
            echo 'Retrieval of data from Database Failed - #'.mysql_errno().': '.mysql_error();
        }else{
    ?>
    <tbody>
    <?php
            if( mysql_num_rows( $selectRes )==0 ){
    
            }else{
                while( $row = mysql_fetch_assoc( $selectRes ) ){
                  echo "<tr><td>{$row['user_ID']}</td><td>{$row['ResourceName']}</td><td>{$row['ResourceType']}</td><td>{$row['ResourceLocation']}</td><td>{$row['ReservationTime']}</td>";
                  $active = $_SESSION['usr'] == $row['user_ID'];
                  echo "<td>"."<button class='btn' type='submit' id='1'".($active ? "" : "disabled").">"."Delete"."</button>"."</td>";
                }
            }               
    ?>      
    </tbody>
    </table>
    <?php
            mysql_close($connector);
        }
    ?>
    

0 个答案:

没有答案