Question

我有一个错误，很常见，因为我已经看到了几个解决方案，在互联网上都是一样的。我试图在我的Android代码上执行此操作，但它不起作用。

我有一个按钮。这个按钮取决于微调器上的文本，应该让我去一个页面或另一个页面。

这是按钮的xml代码：

<Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="@string/lancer"
    android:id="@+id/startButton"
    android:layout_alignParentRight="true"
    android:layout_alignParentBottom="true"
    android:clickable="true"
    android:onClick="jumpTo"/>

及其java类：

public class Admin extends AppCompatActivity implements View.OnClickListener {

Spinner spinner_event;
Spinner spinner_activity;
Spinner spinner_wallpaper;
ArrayAdapter<CharSequence> adapter_wallpaper;
ArrayAdapter<CharSequence> adapter_event;
ArrayAdapter<CharSequence> adapter_activity;
Button startButton;
String textActivity;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.content_admin);


    spinner_event = (Spinner)findViewById(R.id.spinner_event);
    adapter_event = ArrayAdapter.createFromResource(this, R.array.events,android.R.layout.simple_spinner_dropdown_item);
    spinner_event.setAdapter(adapter_event);


    spinner_activity = (Spinner)findViewById(R.id.spinner_activity);
    adapter_activity = ArrayAdapter.createFromResource(this, R.array.activity,android.R.layout.simple_spinner_dropdown_item);
    spinner_activity.setAdapter(adapter_activity);


    spinner_wallpaper = (Spinner)findViewById(R.id.spinner_wallpaper);
    adapter_wallpaper = ArrayAdapter.createFromResource(this, R.array.wallpapers,android.R.layout.simple_spinner_dropdown_item);
    spinner_wallpaper.setAdapter(adapter_wallpaper);

    startButton = (Button)findViewById(R.id.startButton);
    startButton.setOnClickListener(this);
    }

@Override
public void onClick(View v) {
    textActivity = spinner_activity.getSelectedItem().toString();
    switch(v.getId()){

        case R.id.startButton:
        {
            if(textActivity == "Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            break;
        }
    }
}
}

我应该去我的BadgeEntree。它们都是在AndroidManifest.xml上定义的，我很遗憾一切似乎还可以，但事实并非如此，我做错了什么？

感谢您的帮助

Answer 1

删除

startButton.setOnClickListener(this); } @Override public void onClick(View v) { textActivity = spinner_activity.getSelectedItem().toString(); switch(v.getId()){ case R.id.startButton: { if(textActivity == "Entree"){ Intent i = new Intent(this, BadgeEntree.class); startActivity(i); } break; } }

<强>不要

首先，您应该拨打if(textActivity.equals("Entree")而不是==

FYI

现在，当您单击该按钮时，Android系统将调用该按钮 activity的jumpTo（View）方法。为了使这个工作，方法必须是公开的并接受View作为其唯一参数。

public void jumpTo(View i) { textActivity = spinner_activity.getSelectedItem().toString(); if(textActivity.equals("Entree"){ Intent i = new Intent(this, BadgeEntree.class); startActivity(i); } else { Log.d("Else","Wrong"); } }

<强>最后

public class Admin extends AppCompatActivity { Spinner spinner_event; Spinner spinner_activity; Spinner spinner_wallpaper; ArrayAdapter<CharSequence> adapter_wallpaper; ArrayAdapter<CharSequence> adapter_event; ArrayAdapter<CharSequence> adapter_activity; Button startButton; String textActivity; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.content_admin); spinner_event = (Spinner)findViewById(R.id.spinner_event); adapter_event = ArrayAdapter.createFromResource(this, R.array.events,android.R.layout.simple_spinner_dropdown_item); spinner_event.setAdapter(adapter_event); spinner_activity = (Spinner)findViewById(R.id.spinner_activity); adapter_activity = ArrayAdapter.createFromResource(this, R.array.activity,android.R.layout.simple_spinner_dropdown_item); spinner_activity.setAdapter(adapter_activity); spinner_wallpaper = (Spinner)findViewById(R.id.spinner_wallpaper); adapter_wallpaper = ArrayAdapter.createFromResource(this, R.array.wallpapers,android.R.layout.simple_spinner_dropdown_item); spinner_wallpaper.setAdapter(adapter_wallpaper); startButton = (Button)findViewById(R.id.startButton); } public void jumpTo(View i) { textActivity = spinner_activity.getSelectedItem().toString(); if(textActivity.equals("Entree"){ Intent i = new Intent(this, BadgeEntree.class); startActivity(i); } else { Log.d("Else","Wrong"); } } }

Answer 2

从按钮xml代码中删除 onClick标记

Answer 3

删除android：onClick =＆＃34; jumpTo＆＃34;在xml中

<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/lancer"
android:id="@+id/startButton"
android:layout_alignParentRight="true"
android:layout_alignParentBottom="true"
android:clickable="true"
/>

Answer 4

您必须删除此行

  <Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="@string/lancer"
    android:id="@+id/startButton"
    android:layout_alignParentRight="true"
    android:layout_alignParentBottom="true"
    android:clickable="true"
    android:onClick="jumpTo" <-----

/＆GT;

并在您的类中移动jumpTo方法的逻辑，因为现在您在类和xml中都有onCLick侦听器。也改变这一行

if(textActivity == "Entree")

用这个..

if(textActivity.equals("Entree"))

Answer 5

if(textActivity == "Entree")

将上述代码更改为

if(textActivity.equalsIgnoreCase("Entree"))

还从ur xml中删除以下代码

android:onClick="jumpTo"

注意：您可以使用＆＃34; equalsIgnoreCase＆＃34;如果你想要字符串的Case Insensitive比较，如果你想要字符串的Case Sensitive比较，那么你可以使用＆＃34; equals＆＃34;。

onClick事件不适用于Android

5 个答案:

FYI