Backbone Model urlroot

Question

这些是我服务器的路径网址：

GET /watchlists
GET /watchlists/:id
POST /watchlists // Create a new watchlists
PUT /watchlists/:id // Change attributes of watchlists (Like name)
POST /watchlists/:id/movies // Add a movie
DELETE /watchlists/:id/movies/:trackId //  Delete a movie by the trackid
DELETE /watchlists/:id // Delete the watchlists by is ID

这是我的模特：

var WatchlistModel = Backbone.Model.extend({
    urlRoot: '/watchlists',
});

我想知道怎样做＆＃39;添加电影＆＃39;用这个网址：

/watchlists/:id/movies 

和删除电话：

/watchlists/:id/movies/:trackId

对此有哪些最佳实践？

Answer 1

一种解决方案是将Movies集合创建为每个WatchlistModel模型的子集，为其提供其父级的引用，并使用该引用构建其url。

假设对父项的引用存储在watchlist属性中，如

var Movies = Backbone.Collection.extend({
    url: function() {
       return _.result(this.watchlist, 'url') + '/movies';
    }
});

var WatchlistModel = Backbone.Model.extend({
    urlRoot: '/watchlists',
    initialize: function() {
        this.movies = new Movies();
        this.movies.watchlist = this;
    }
});

你会创建一个这样的新电影：

var lst = new WatchlistModel({id: 1});
var newmovie = lst.movies.create();