Question

我想使用libGDX检查网络连接，并尝试使用以下代码。

HttpRequestBuilder requestBuilder = new HttpRequestBuilder();
Net.HttpRequest httpRequest = requestBuilder.newRequest().method(Net.HttpMethods.GET).url("https://api.vk.com/").build();

Net.HttpResponseListener httpResponseListener = new httpResponseListener() {
    public void handleHttpResponse (Net.HttpResponse httpResponse) {
        HttpStatus status = httpResponse.getStatus();
        if (status.getStatusCode() >= 200 && status.getStatusCode() < 300) {
            // it was successful
        } else {
            // do something else
        }
    }
}

Gdx.net.sendHttpRequest(httpRequest, httpResponseListener);

它有几个错误，例如Gdx.net现在没有sendHttpRequest()功能。我该如何更正此代码？

Answer 1

Gdx.net有sendHttpRequest()方法 - 您似乎使用的不是HttpRequest实例（为什么Net...以大写字母开头？）

关于如何使用Gdx.net的一个适当的最小示例是 - 我还在必要时添加了评论

    public class HttpManager implements HttpResponseListener 
    {   
        public HttpState state;
        private String result;
        private byte[] byteResult;

        HttpRequest request;

        public HttpManager()
        {
            request = new HttpRequest();
            request.setMethod(Net.HttpMethods.GET); //or POST
            request.setContent(""); //you can put here some PUT/GET content
            request.setUrl(url);
            Gdx.net.sendHttpRequest(request, this);
        }

        @Override
        public void handleHttpResponse(HttpResponse httpResponse) 
        {
            if( httpResponse.getStatus().getStatusCode() != 200 )
            {
                //ERROR
                float errorCode = httpResponse.getStatus().getStatusCode();
            }
            else
            {
                byte[] byteResult = httpResponse.getResult(); //you can also get result as String by using httpResponse.getResultAsString();
            }   
        }

        @Override
        public void failed(Throwable t) 
        {
            // TODO Auto-generated method stub  
        }

        @Override
        public void cancelled() 
        {
            // TODO Auto-generated method stub  
        }
    }

检查libGDX中的网络连接

1 个答案: