Question

我想问一下是否有人可以帮助他让这段代码发挥作用。我的MySQL数据库中没有任何内容出现。谢谢，enbr。

NSString *urlstr = [[NSString alloc] initWithFormat:@"http://mysite.come/myapp/submitrating.php?name=%@&comment=%@&rating=%@",
                    [selectedItem objectForKey:@"name"], comment.text, selectedRating];
NSString *urlstrEncoded = [urlstr stringByReplacingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [[NSURL alloc] initWithString:urlstrEncoded];
[urlstr release];
[url release];

Answer 1

你需要做的远不止这些！至少您需要以下内容：

NSMutableURLRequest *theRequest = [NSMutableURLRequest requestWithURL:theURL cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:10.0];



NSURLConnection *theConnection = [[NSURLConnection alloc] initWithRequest:theRequest delegate:self];

以及实施以下方法：

-(void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error
-(void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response

Answer 2

除了创建URL对象之外，你不是使用做任何事情。也许您想尝试NSURLConnection？

Answer 3

我让它使用此代码。

NSString *urlstr = [NSString stringWithFormat:@"http://mysite.com/myapp/submitrating.php?name=%@&comment=%@&rating=%@", [selectedItem objectForKey:@"name"], comment.text, selectedRating];
NSString *urlEncoded = [urlstr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSURL *url = [[NSURL alloc] initWithString:urlEncoded];
NSString *ans = [NSString stringWithContentsOfURL:url encoding:NSASCIIStringEncoding error:nil];

NSURL无法正常工作

3 个答案: