Twitter API无法授权(Android)

时间:2016-03-09 11:27:47

标签: android twitter twitter-fabric

抱歉我的英文。我无法理解为什么我无法在app中授权。我使用twitter文档,但是当我在twitter中输入登录名和密码时,没有任何反应,代码中的回调不起作用。

对于图片中的链接感到抱歉,我没有15点声誉

我在Twitter中的设置

image http://take.ms/SQcRO

当我点击此按钮时,没有任何反应:

image http://take.ms/4Xo9R

我的代码:

  TwitterAuthConfig authConfig = new TwitterAuthConfig(TWITTER_KEY, TWITTER_SECRET);
    Fabric.with(this, new Twitter(authConfig));
    setContentView(R.layout.activity_main);

    status = (TextView)findViewById(R.id.status);
    status.setText("Status: Ready");

    loginButton = (TwitterLoginButton) findViewById(R.id.twitter_login_button);
    loginButton.setCallback(new Callback<TwitterSession>() {
        @Override
        public void success(Result<TwitterSession> result) {
            Log.e("success", "success");
            // The TwitterSession is also available through:
            // Twitter.getInstance().core.getSessionManager().getActiveSession()
            TwitterSession session = result.data;
            // TODO: Remove toast and use the TwitterSession's userID
            // with your app's user model
            String msg = "@" + session.getUserName() + " logged in! (#" + session.getUserId() + ")";
            Log.e("msg", msg);
            Toast.makeText(getApplicationContext(), msg, Toast.LENGTH_LONG).show();
        }

        @Override
        public void failure(TwitterException exception) {
            status.setText("Status: Login Failed");
            Toast.makeText(getApplicationContext(), exception.toString(), Toast.LENGTH_SHORT).show();
            Log.d("error", "Login with Twitter failure", exception);
        }
    });
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    // Make sure that the loginButton hears the result from any
    // Activity that it triggered.
    loginButton.onActivityResult(requestCode, resultCode, data);
}

在调试器中未输入此行:loginButton.onActivityResult(requestCode, resultCode, data);

我不知道为什么它不起作用。

0 个答案:

没有答案
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