Question

我在两个不同的while循环中从数据库中获取数据，我想在循环之外添加它们之间的变量。示例：

while($cash_fetch = mysql_fetch_array($cash_qur))
{
      $a = 500; //suppose I am fetching from database
}

while($card_fetch = mysql_fetch_array($card_qur))
{
    $b = 1000; //suppose I am fetching from database
}

$total = $a+$b;

echo $total;

我想完全做这件事，但结果不合适。请帮忙。

Answer 1

你可以试试这个 -

$a = $b = 0; // set to 0 by default
while($cash_fetch = mysql_fetch_array($cash_qur))
{
    $a += 500; //Increment
}

while($card_fetch = mysql_fetch_array($card_qur))
{
    $b += 1000; //Increment
}
$total = $a + $b;
echo $total;

Answer 2

你可能想这样做：

DECLARE
  v_list sys.Odcinumberlist := sys.Odcinumberlist( 1, 2, 3, 4 );
  v_member_found char(3);
BEGIN

  FOR i IN 1..v_list.COUNT LOOP
    dbms_output.put_line( v_list(i) );
  END LOOP;

  begin
   select 'yes' into v_member_found 
    from table(v_list) 
   where column_value = 1;
  exception
    when no_data_found 
     then v_member_found := 'no';
  end;
  dbms_output.put_line(v_member_found);

END;

Answer 3

你可以试试这个：

$a = 0;
$b = 0;
while($cash_fetch = mysql_fetch_array($cash_qur))
{
      $a = 500; //suppose I am fetching from database
}

while($card_fetch = mysql_fetch_array($card_qur))
{
    $b = 1000; //suppose I am fetching from database
}

$total = $a+$b;

echo $total;

在两个不同的while循环中添加数字

3 个答案: