Question

游戏要求用户在1和5之间输入一个数字，看看它们是否与计算机随机猜测匹配。

当我到达if else语句时，我的代码似乎无法正常工作，并且无法解决问题。

from random import randint 

print "I am thinking of a number between 1 and 5";
print "What do you think the number is that I am thinking of", 
guess = raw_input("> ")
cguess = (randint(1,5))

print "Your guess was", guess, 
print "\nMine was", cguess,

if guess == cguess
    print "Well done you win"
if guess != cguess
    print "You lose"

Answer 1

import random

guess = int(input('guess a no between 1 to 5 :'))
cguess = random.randint(1,5)

if guess == cguess: 
    print('Well done you win')
else:
    print('You lose')

Answer 2

您在:声明的末尾缺少冒号（if）。

if guess == cguess:
    print("Well done you win!")
else:
    print("You lose")

它正在跳过guess == cguess条件，因为raw_input()会返回string，而不是int。首先展开cguess变量（str(cguess)）。

Answer 3

raw_input返回一个字符串，因此您将字符串与整数进行比较。你需要把字符串变成一个整数

guess = int(raw_input("> ")) # <----- see the int call

现在猜= = cguess会起作用（如果你猜对了）

Python初学者（猜猜随机数游戏）

3 个答案: