Question

我有一个输入字段，其中包含来自控制器（ControllerA）的值。现在我想只将输入字段保存到另一个表中。

ControllerA：

public function makeentry($id = null, $value){

    //Here i get the correctly value in the input field 
    $controllerA = $this->ControllerA->get($id);

    //Connect to the other table (?)
    $controllerBTable = TableRegistry::get('ControllerB');
    $controllerB = $controllerBTable->newEntity();

    //Dosn't work here and no error message
    if ($this->request->is('post')) {

            $controllerB->name = $this->request->data;

            if ($controllerBTable->save($controllerB)) {
                $this->Flash->success(__('Saved.'));

                //Go back to ConntrolerA
                return $this->redirect(['action' => 'index']);
            }else{
                $this->Flash->error('Could not be saved.');
            }               
        }

        //set the value into the input-field
        $this->set('controllerA', $controllerA);
    }
}

在model-＆gt;表中

表A：

public function initialize(array $config)
    {
        $this->table('tableA');
        $this->displayField('name');
        $this->primaryKey('id');
        $this->belongsTo('TableB');
    }

表B：

public function initialize(array $config)
    {
        $this->table('tableA');
        $this->displayField('name');
        $this->primaryKey('id');
        $this->belongsTo('TableA');
    }

有人可以用简单的单词或示例代码解释它如何实现它

Answer 1

您可以按照以下步骤进行操作保存表1中的数据


    $saveData = $this->request->data;
    $this->loadModel('Table1');
    $this->Table1->save($saveData);

同样，您可以在任何表中保存数据


    $saveData = $this->request->data;
    $this->loadModel('Table2');
    $this->Table2->save($saveData);

你也可以选择这个


    $saveData = array();
    $saveData['field_name_1'] = $this->data[$this->modelClass]['field_name_1'];
    $saveData['field_name_2'] = $this->data[$this->modelClass]['field_name_2'];
    $this->{$this->modelClass}->save($saveData);

cakephp将数据保存到另一个表中

1 个答案: