Question

这就是我想要的。

＆＃13;

var object1 = {name: 'one', psno:'34'};
var object2 = {name: 'two', psno:'34'};
var object3 = {name: 'three', psno:'345'};
var arr1 = [object1,object2,object3];
var arr2 = [object1,object2];
// solution
var names = arr1.map(function(obj) { 
  return obj.name; 
});
var isSuperset = arr2.every(function(val) { 
  return names.indexOf(val) >= 0;
});
alert(isSuperset);

＆＃13;

它返回false而不是true。哪里出错了。

Answer 1

那是因为你在检查.name时没有.indexOf

var object1 = {
  name: 'one',
  psno: '34'
};
var object2 = {
  name: 'two',
  psno: '34'
};
var object3 = {
  name: 'three',
  psno: '345'
};
var arr1 = [object1, object2, object3];
var arr2 = [object1, object2];
// solution
var names = arr1.map(function(obj) {
  return obj.name;
});
var isSuperset = arr2.every(function(val) {
//Ive changed this line!
  return names.indexOf(val.name) >= 0;
});
alert(isSuperset);

JS小提琴： https://jsfiddle.net/waqmafsa/

Answer 2

这是一种检查对象中所有键/值匹配的方法。

// creates a hash for each object
// e.g. "name|one|psno|34"
function hash(obj) {
  return Object.keys(obj).reduce(function(p, c) {
    return p.concat([c, obj[c]].join('|'));
  }, []).sort().join('|');
}

// returns a hashed object
function hashObject(obj) {
  return hash(obj);
}

// returns a function that checks to see
// if an element is in the array
function within(arr) {
  return function (el) {
    return arr.indexOf(el) > -1;
  }
}

// performs the check    
function check(arr1, arr2) {
  if (arr1.length < arr2.length) return false;
  var hashedArr1 = arr1.map(hashObject);
  return arr2.map(hashObject).every(within(hashedArr1));
}

var issubset = check(arr1, arr2);

DEMO

检查对象数组是否是另一个对象数组

2 个答案: