Python:如何处理CSV中的缺失值?

时间:2016-03-18 06:10:47

标签: python csv python-2.x

我有一个给定的CSV样本如下:

ID,ID_TYPE,OB_DATE,VERSION_NUM,MET_DOMAIN_NAME,OB_END_CTIME,OB_DAY_CNT,SRC_ID,REC_ST_IND,PRCP_AMT,OB_DAY_CNT_Q,PRCP_AMT_Q,METO_STMP_TIME,MIDAS_STMP_ETIME,PRCP_AMT_J
90, RAIN, 2006-01-01 00:00,1, WADRAIN,900,1,24109,1011,0,0,6, 2006-01-17 09:04,0,
150, RAIN, 2006-01-01 00:00,1, DLY3208,900,1,30747,1011,0,0,6, 2006-01-09 13:21,3,
174, RAIN, 2006-01-01 00:00,1, WADRAIN,900,1,24775,1011,0.2,0,6, 2006-01-17 09:04,0,

我想在CSV中确定每个指定日期的工作日。我的代码实现如下:

import csv
from datetime import datetime as dt


csv_file = open('raindata.csv')
csv_reader = csv.DictReader(csv_file)
field_names = list(csv_reader.fieldnames)
if 'WEEKDAY' in field_names:
    print "data has error"

elif 'RECWEEKDAY' in field_names:
    print "data has error"

else:
    field_names.insert(field_names.index('OB_DATE') + 1, 'WEEKDAY')
    field_names.insert(field_names.index('METO_STMP_TIME') + 1, 'RECWEEKDAY')

    def get_weekday(ob_date):
        return dt.strptime(ob_date, ' %Y-%m-%d %H:%M').strftime('%A')

    output = open('raindata.csv','w')
    csv_writer = csv.DictWriter(output, field_names)
    csv_writer.writeheader()
    for row in csv_reader:
        row['WEEKDAY'] = get_weekday(row['OB_DATE'])
        row['RECWEEKDAY'] = get_weekday(row['METO_STMP_TIME'])
        csv_writer.writerow(row)

我的脚本运行正常并提供了正确的结果,但在 OB_DATE 列和 METO_STMP_TIME 列中缺少Date值时失败。

如何更改现有代码,以便对于空白Date值,相应的Weekday值也为空?

2 个答案:

答案 0 :(得分:2)

只捕获日期/时间字符串丢失或无效时引发的异常,然后将该值设置为空字符串。

try:
    row['WEEKDAY'] = get_weekday(row['OB_DATE'])
except ValueError:
    row['WEEKDAY'] = ''

答案 1 :(得分:2)

对于其他选择,您可以修改get_weekday功能以处理空白日期。

def get_weekday(ob_date):
    return dt.strptime(ob_date, ' %Y-%m-%d %H:%M').strftime('%A') if ob_date.strip() else ""
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