Question

我正在尝试使用一系列数字从表中选择数据。总之，我想选择数字在6到9范围内的路径

$sql = "select * from users where path_name like  between '%6%' and '%9%' ";

但没有任何回报。

任何人都有更好的方法吗？

Answer 1

您不需要like

如果您想返回6和9之间的所有数字：

$sql = "select * from users where path_name between 6 and 9";

Answer 2

这就是我在寻找的人

$sql1 = "select * from users where path_name REGEXP '[6-9]'"; 参考 Regular expressions

Example of regular expression in sql

Answer 3

由于path_name是数字，您应该使用条件语句。考虑使用where path_name >= 6 and path_name <= 9或更简单的5和10，条件很好。

Answer 4

SELECT * FROM USERS
WHERE SUBSTR(PATH_NAME, 4, len(PATH_NAME)-4) BETWEEN 6 and 9

我想你的path_name值就像'axr6b'

Answer 5

如果是SQL Server，则范围匹配可以使用Like

declare @users table (path_name varchar(10)) 
insert @users values
     ('download1'), ('download3'), ('download5'), ('download6'), 
     ('download7'), ('download9'), ('download10')

select * from @users where path_name like '%[6-9]%'

sql选择使用之间和喜欢

5 个答案: