Question

我通过soap api oracle服务云获取此格式的日期

2016-03-08T06：20：16Z

如何通过VB中的函数翻转它？

Answer 1

 Function DateFlip(D As String)
        Try
            Dim result As String() = D.Split(New String() {"-", "T", "Z", ":"}, StringSplitOptions.None)
            Dim test As Integer = CInt(result(3))
            If (test > 12) Then
                Return result(2) + "/" + result(1) + "/" + result(0) + " " + result(3) + ":" + result(4) + ":" + result(5) + " PM"
            Else
                Return result(2) + "/" + result(1) + "/" + result(0) + " " + result(3) + ":" + result(4) + ":" + result(5) + " AM"

            End If

        Catch e As Exception
            Return ""
        End Try

将此功能添加到VB类

DateFlip("2016-03-08T06:20:16Z")

Answer 2

我知道它已经得到了解答，但我在一行中有更好的代码也可以尝试我的

 Dim time As String = "2016-03-08T06:20:16Z"
 MsgBox(CDate(time.Substring(0, 10)).ToString("dd/MM/yyyy") +
 " " +
 CDate(time.Substring(11, 8)).ToString("hh:mm:ss tt"))

VB中的日期翻转功能

2 个答案: