Question

我有两个阵列。

数组1 - 所有日期列表
数组2 - 一个人在场的所有日期列表

我想要显示一个表格，其中包含第一行中的所有日期以及第二行中某个人出现的每一天，相应的列应该表示存在。

我尝试了嵌套循环，但它只显示了每行的各种行和一个结果，即每行只有一个匹配。

我想完成这样的事情

<table width="100%" border="1" cellspacing="1" cellpadding="1">
  <tr>
    <td width="6%">160111</td>
    <td width="6%">160113</td>
    <td width="6%">160120</td>
    <td width="6%">160127</td>
    <td width="6%">160201</td>
    <td width="6%">160203</td>
    <td width="6%">160208</td>
    <td width="6%">160210</td>
    <td width="6%">160217</td>
    <td width="6%">160224</td>
    <td width="6%">160229</td>
    <td width="6%">160302</td>
    <td width="6%">160307</td>
    <td width="6%">160309</td>
    <td width="6%">160321</td>
    <td width="5%">160323</td>
  </tr>
  <tr>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>Present</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>Present</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>Present</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
    <td>&nbsp;</td>
  </tr>
</table>

连连呢？如何运行循环或如何实现？

Answer 1

使用in_array()来测试某个项目是否在数组2中。

foreach ($array1 as $day) {
    echo "<td>";
    echo in_array($day, $array2) ? "Present" : "&nbsp;";
    echo "</td>";
}

Answer 2

如果Array与我在答案中给出的相同，你可以试试这个

PHP代码：

<?php
    $dates =array(
        '160111','160113','160120','160127','160201','160203',
        '160208','160210','160217','160224','160229','160302',
        '160307','160309','160321','160323'  
    );
    $person_present =array(
        '','','','160127','','',
        '','160210','','','','160302',
        '','','',''  
    );

   foreach ($dates as $pkey => $day) 
   {
        if ( in_array($day, $person_present) ) {
            ?>
            <td>Present</td>
           <?php
        } else {
            ?>
            <td>&nbsp;</td>
           <?php
        }        
   }
?>

完整代码：

    <table width="100%" border="1" cellspacing="1" cellpadding="1">
      <tr>
        <td width="6%">160111</td>
        <td width="6%">160113</td>
        <td width="6%">160120</td>
        <td width="6%">160127</td>
        <td width="6%">160201</td>
        <td width="6%">160203</td>
        <td width="6%">160208</td>
        <td width="6%">160210</td>
        <td width="6%">160217</td>
        <td width="6%">160224</td>
        <td width="6%">160229</td>
        <td width="6%">160302</td>
        <td width="6%">160307</td>
        <td width="6%">160309</td>
        <td width="6%">160321</td>
        <td width="5%">160323</td>
      </tr>
      <tr>
 <?php
    $dates =array(
        '160111','160113','160120','160127','160201','160203',
        '160208','160210','160217','160224','160229','160302',
        '160307','160309','160321','160323'  
    );
    $person_present =array(
        '','','','160127','','',
        '','160210','','','','160302',
        '','','',''  
    );

   foreach ($dates as $pkey => $day) 
   {
        if ( in_array($day, $person_present) ) {
            ?>
            <td>Present</td>
           <?php
        } else {
            ?>
            <td>&nbsp;</td>
           <?php
        }        
   }
?>   
      </tr>
    </table>

Answer 3

遍历Array1（foreach循环）
针对Array2（ in_array（））

例如： -

echo "<br/><table border='1' style='width:100%'><tr><td>";
foreach($arr1 as $a1) {
echo "<table border='1' style='display:inline;border:0px solid'>";
echo "<tr><td>$a1</td></tr>";
    if(in_array($a1,$arr2)) {
        echo "<tr><td>Present</td></tr>";
    } else {
        echo "<tr><td> </td></tr>";
    }
    echo "</table>";
}
echo "</td></tr></table>";

如何比较两个数组并在列

3 个答案: