我一直在研究一个使用GZIP压缩字节数组的函数,并通过属于套接字的outputStream发送它。它下载得很好,但是当我试图在我的电脑上解压时,它说文件已损坏。
private void Zip(byte[] datatocompress)
{
ZipOutputStream zippoutstream = new ZipOutputStream(outputstream);
zippoutstream.putNextEntry(new ZipEntry("file.html"));
zippoutstream.write(datatocompress);
zippoutstream.closeEntry();
zippoutstream.flush();
zippoutstream.close();
}
不知道崩溃是什么。有什么建议吗?
答案 0 :(得分:2)
public static byte[] gzip(byte[] val) throws IOException {
ByteArrayOutputStream bos = new ByteArrayOutputStream(val.length);
GZIPOutputStream gos = null;
try {
gos = new GZIPOutputStream(bos);
gos.write(val, 0, val.length);
gos.finish();
gos.flush();
bos.flush();
val = bos.toByteArray();
} finally {
if (gos != null)
gos.close();
if (bos != null)
bos.close();
}
return val;
}
/**
* Compress
*
* @param source
*
* @param target
*
* @throws IOException
*/
public static void zipFile(String source, String target) throws IOException {
FileInputStream fin = null;
FileOutputStream fout = null;
GZIPOutputStream gzout = null;
try {
fin = new FileInputStream(source);
fout = new FileOutputStream(target);
gzout = new GZIPOutputStream(fout);
byte[] buf = new byte[1024];
int num;
while ((num = fin.read(buf)) != -1) {
gzout.write(buf, 0, num);
}
} finally {
if (gzout != null)
gzout.close();
if (fout != null)
fout.close();
if (fin != null)
fin.close();
}
}