我目前正在尝试用Java解析XML文件。我已经做了很多研究，并尝试使用许多可用的库，如DOM，SAX等。所有这些都很棒并且有很多选择。我的问题是，我希望能够解析整个XML文件，然后输出可能存在的任何错误。以SAX为例，它将解析文件，但只输出第一个语法错误。有没有像编译器一样输出所有错误，或者我运气不好？
如果无法做到这一点，我正在尝试解析我的XML文件，就像普通文本文件一样，并抓住所有开始和结束标记。除了创建许多条件语句和规则之外，还有更简单的方法吗？
非常感谢任何帮助。
由于
答案 0 :(得分：0)
只需使用自定义 public class MyFirebaseMessagingService extends FirebaseMessagingService {
private static final String TAG = "FCM Service";
@Override
public void onMessageReceived(RemoteMessage remoteMessage) {
// TODO: Handle FCM messages here.
// If the application is in the foreground handle both data and notification messages here.
// Also if you intend on generating your own notifications as a result of a received FCM
// message, here is where that should be initiated.
Log.d(TAG, "From: " + remoteMessage.getFrom());
Log.d(TAG, "Notification Message Body: " + remoteMessage.getNotification().getBody());
sendNotification("deneme",remoteMessage.getNotification().getBody());
}
int mNotificationId = 001;
private void sendNotification(String messageTitle,String messageBody)
{
Intent notificationIntent = new Intent(this, LoginActivity.class);
// set intent so it does not start a new activity
notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
PendingIntent resultPendingIntent = PendingIntent.getActivity(this,0,notificationIntent,PendingIntent.FLAG_CANCEL_CURRENT);
NotificationCompat.InboxStyle inboxStyle = new NotificationCompat.InboxStyle();
NotificationCompat.Builder notificationBuilder = new NotificationCompat.Builder(this);
notificationBuilder.setSmallIcon(R.drawable.ic_launcher);
notificationBuilder.setContentTitle(messageTitle);
notificationBuilder.setContentText(messageBody);
notificationBuilder.setAutoCancel(true);
notificationBuilder.setContentIntent(resultPendingIntent);
Notification notification = notificationBuilder.build();
NotificationManager notificationManager =(NotificationManager) getSystemService(Context.NOTIFICATION_SERVICE);
try {
Uri alarmSound = Uri.parse(ContentResolver.SCHEME_ANDROID_RESOURCE+ "://" + this.getPackageName() + "/raw/notification");
Ringtone r = RingtoneManager.getRingtone(this, alarmSound);
r.play();
} catch (Exception e) {
e.printStackTrace();
}
notificationManager.notify(632623,notification );
}
}
（作为默认ErrorHandler在第一次出错时抛出异常）。
ErrorHandler答案 1 :(得分：-1)
我认为您在找到这种类型的XML解析器方面会取得很大成功。根据定义，XML解析器应该在遇到的第一个错误时抛出异常。如果它没有，它将无法识别任何后续文本的节点类型或正确性......