Question

这是我的数据库结构。表名LOPList：

a busy cat http://i65.tinypic.com/2ebtyr9.png

我有这个SQL：

select LOPID, EmpId,
       max(case when LOPStatus = 'Y' then TimeUpdated end) as time_start,
       max(case when LOPStatus = 'N' then TimeUpdated end) as time_end
from MultipleLOPStatus
where JobID = 83
group by LOPID

结果是

LOPID | EmpId    | time_start                | time_end
33    |   28     | 2016-03-27T09:33:05-03:00 |  2016-03-27T11:49:17-03:00`

我希望结果如下：

 LOPID |    EmpId    | time_start                | time_end
33     |    28       | 2016-03-27T09:23:17-03:00 | 2016-03-27T09:31:59-03:00
33     |    28       | 2016-03-27T09:32:30-03:00 | 2016-03-27T11:49:17-03:00
33     |    30       | 2016-03-27T09:33:05-03:00 | 2016-03-27T11:48:53-03:00 `

我们如何实现这一目标？

Answer 1

如果我理解正确，你只想获得每个相应time_start的time_end。在这种情况下，您不需要使用条件聚合，您可以使用相关查询来实现此目的：

SELECT s.LOPID, s.EmpId,s.timeUpdated as time_start,
       (SELECT MIN(timeUpdated) FROM MultipleLOPStatus t
        WHERE s.LOPID = t.LOPID and t.empid = s.empid and t.LOPStatus = 'N'
          AND t.timeUpdated > s.TimeUpdated) as time_end
from MultipleLOPStatus s
where s.JobID = 83
 AND s.LOPStatus = 'Y'

使用Group Concat重复区域

1 个答案: