Question

新的stackflow，我希望我的问题可以帮助其他python新手。

我正在尝试创建一个执行以下操作的程序： 1. secret_num ==在1-10之间生成随机＃ 2.要求用户在1-10之间猜测这个数字 3.如果guess == secret_num祝贺他们并提供猜测的number_guesses数量（减去任何重复的猜测） 4.重复猜测的帐户 5.让他们知道猜测是否过高或过低

我知道这对你们很多人来说都是abc的东西，但我在语法，缩进和控制流方面遇到了典型的新程序员问题。现在我在elif guess == secret num上得到一个语法。否则我无法使用此代码来解决重复问题以挽救我的生命。我将不胜感激任何帮助。谢谢。

import random

def game():
# generate a random number between 1 -100 and initiate repeat guess list
    secret_num=random.randint(1,10)
# initiate duplicate list and number of guesses
    already_guesses = []
    number_guesses = 0

    while True:
# ask for user guess
        guess = int(input('Guess a number from 1-10> '))
# help with guesses and announce if it is correct number!
# catch someone if they submit the same number
        if guess in already_guesses:
            print ("You already guessed that number, try again")
        already_guesses.append(guess)
        number_guesses += 1
        elif guess == secret_num:
            print("whooohoo! you guessed it, my number is {}".format(secret_num))
            print("It took you {} guesses".format(number_guesses - len([already_guesses])))
            break
        elif guess < secret_num:
            print("You\'re getting hot, try a higher number")
        else:
            guess > secret_num
            print("You\'re cold, try a lower number")
# ask if they want to play again
    else:
        play_again = input("Do you wanna play again? y/n")
        if play_again != 'n':
            game()
        else:
            print("Bah Bye!")

game()

Answer 1

您的代码还存在其他一些问题（在评论中提到缩进之后）：

var exports = {};
importScripts('b64.js')

onmessage = function(e) {
  var base64Bytes = fromByteArray(new Uint8Array(e.data));
  postMessage(base64Bytes);
};

初学者：使用elif控制流和语法错误

1 个答案: