Question

这个代码在localhost上工作，但我得到了＆＃34; basicNetwork.performRequest：意外的响应代码500＆＃34;如果我将此文件放在在线服务器上，则会出错

这是我的重要项目......请帮助我......

private void Login(final String email, final String password) {
    // Tag used to cancel the request
    String tag_string_req = "req_login";

    pDialog.setMessage("Logging in ...");
    showDialog();

    StringRequest strReq = new StringRequest(Request.Method.POST,
            Functions.LOGIN_URL, new Response.Listener<String>() {

        @Override
        public void onResponse(String response) {
            Log.d(TAG, "Login Response: " + response.toString());
            hideDialog();

            try {
                JSONObject jObj = new JSONObject(response);
                boolean error = jObj.getBoolean("error");

                // Check for error node in json
                if (!error) {
                    JSONObject json_user = jObj.getJSONObject("user");
                    Toast.makeText(getApplicationContext(), "Successful!", Toast.LENGTH_LONG).show();

                } else {
                    Toast.makeText(getApplicationContext(), "Incorrect email or password!", Toast.LENGTH_LONG).show();
                }
            } catch (JSONException e) {
                // JSON error
                e.printStackTrace();
                Toast.makeText(getApplicationContext(), "Json error: " + e.getMessage(), Toast.LENGTH_LONG).show();
            }

        }
    }, new Response.ErrorListener() {

        @Override
        public void onErrorResponse(VolleyError error) {
            Log.e(TAG, "Login Error: " + error.getMessage());
            Toast.makeText(getApplicationContext(), error.getMessage(), Toast.LENGTH_LONG).show();
            hideDialog();
        }
    }) {

        @Override
        protected Map<String, String> getParams() {
            // Posting parameters to login url
            Map<String, String> params = new HashMap<String, String>();
            params.put("tag", "login");
            params.put("email", email);
            params.put("password", password);

            return params;
        }

        @Override
        public Map<String, String> getHeaders() throws AuthFailureError {
            Map<String,String> params = new HashMap<String, String>();
            params.put("Content-Type","application/x-www-form-urlencoded");
            return params;
        }

    };

    // Adding request to request queue
    MyApplication.getInstance().addToRequestQueue(strReq, tag_string_req);
}

Answer 1

500是服务器错误！你应该查看你的脚本！

basicNetwork.performRequest：意外的响应代码

1 个答案: