Question

我有一系列电话号码对象，电话号码型号如下：

@property NSString *hotlineName;
@property NSString *hotlineNameAr;
@property NSString *hotlineNumber;
@property NSString *hotlineImage;
@property NSInteger hotlineID;
@property RLMArray<Tags> *hotlineTags;

当我执行搜索时，如果hotlineName，hotlineNameAr，hotlineNumber和属性hotlineTags：tagName和tagNameAr包含搜索文本，我会过滤数组。

我使用NSPredicate来过滤数组：

 -(void) searchForText: (NSString *) searchText{

  NSString *predicateFormat = @"SELF.%K contains[cd] %@";
  NSString *tagFormat = @"ANY SELF.hotlineTags.%K contains[cd] %@";

  NSString *searchNameAttribute = @"hotlineName" ;
  NSString *searchTagAttribute = @"tagName";
  NSString *searchNameAttribute_ar = @"hotlineNameAr" ;
  NSString *searchTagAttribute_ar = @"tagNameAr";
  NSString *numberAttribute = @"hotlineNumber";

  NSPredicate *namePredicate = [NSPredicate  predicateWithFormat:predicateFormat, searchNameAttribute, searchText];

  NSPredicate *tagPredicate = [NSPredicate predicateWithFormat:tagFormat, searchTagAttribute, searchText];

  NSPredicate *namePredicate_ar = [NSPredicate predicateWithFormat:predicateFormat, searchNameAttribute_ar, searchText];

  NSPredicate *tagPredicate_ar = [NSPredicate predicateWithFormat:tagFormat, searchTagAttribute_ar, searchText];

  NSPredicate *numberPredicate = [NSPredicate predicateWithFormat:predicateFormat, numberAttribute, searchText];

  NSPredicate *predicate = [NSCompoundPredicate orPredicateWithSubpredicates:@[namePredicate, numberPredicate, tagPredicate, namePredicate_ar, tagPredicate_ar]];

  filteredResults = [hotlines_arr filteredArrayUsingPredicate:predicate]; 
}

到目前为止它运行良好，当我用不同的语言环境搜索数字时出现问题，在这个例子中是阿拉伯语，因此我使用了NSNumberFormatter：

// Convert string From Arabic/Persian numbers to English numbers
+(NSString *) convertToEnglishNumber:(NSString *) string {

    // NSNumericSearch
    NSNumberFormatter *formatter = [[NSNumberFormatter alloc] init];
    formatter.numberStyle = NSNumberFormatterDecimalStyle;
    NSLocale *locale = [NSLocale localeWithLocaleIdentifier:@"EN"];
    [formatter setLocale:locale];
    NSNumber *number = [formatter numberFromString:string];

    return [number stringValue];

}

但是NSNumberFormatter的问题在于转换中忽略了任何前导零，所以我需要一种替代方法来根据区域设置或搜索数组格式化NSString，同时考虑区域设置，聚光灯搜索中的相同选项。我也尝试过格式化，但这是徒劳的。

NSString *str = [[NSString alloc] initWithFormat:@"%@" locale:locale, searchText];

NSString *localizedString =[NSString localizedStringWithFormat:@"%@", searchText];

Answer 1

由于我无法想到任何其他选项，这是最后的选择，我最终更换了字符串，但我对答案非常不满意：

+ (NSString *) replaceStrings: (NSString *) textToEdit{
    NSLocale *locale = [NSLocale localeWithLocaleIdentifier:@"ar"];
    for (NSInteger i= 0; i < 10; i++) {
        NSString *stringVal = [@(i) stringValue];
        NSString *localeString = [@(i) descriptionWithLocale:locale];
        textToEdit = [textToEdit stringByReplacingOccurrencesOfString:localeString withString:stringVal];
    }
    return textToEdit;
}

在NSArray中搜索具有不同语言环境的对象

1 个答案: