Question

我在symfony2中运行phpunit，并且看到每个日志条目输出到stdout。

我已从所有config.yml文件中删除了所有monolog处理程序和其他配置条目，因此假设它是symfony-phpunit网桥的默认设置或其他内容。

这是我的phpunit.xml.dist：

<?xml version="1.0" encoding="UTF-8"?>

<!-- http://phpunit.de/manual/4.1/en/appendixes.configuration.html -->
<phpunit xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:noNamespaceSchemaLocation="http://schema.phpunit.de/4.1/phpunit.xsd"
         backupGlobals="false"
         colors="true"
         bootstrap="app/autoload.php"
>
    <php>
        <ini name="error_reporting" value="-1" />
    </php>

    <testsuites>
        <testsuite name="Project Test Suite">
            <directory>tests</directory>
        </testsuite>
    </testsuites>

    <php>
        <server name="KERNEL_DIR" value="app/" />
    </php>

    <listeners>
        <listener class="\Mockery\Adapter\Phpunit\TestListener"
                  file="Mockery/Adapter/Phpunit/TestListener.php">
        </listener>
    </listeners>

    <filter>
        <whitelist>
            <directory>src</directory>
            <exclude>
                <directory>src/*Bundle/Resources</directory>
                <directory>src/*/*Bundle/Resources</directory>
                <directory>src/*/Bundle/*Bundle/Resources</directory>
            </exclude>
        </whitelist>
    </filter>
</phpunit>

有关删除此输出的任何想法？

ETA，测试使用实例化的monolog实例，如下所示：

 /**
   * @return Logger
   */
  protected function getLogger() {
    $logger = new Logger('test');
    $logger->pushHandler(new DebugHandler);
    return $logger;
  }

（删除debugHandler无效）。

它的行为类似于有一个输出到stdout的处理程序，但事实并非如此。以下是我运行phpunit时的一些输出：

 Matthews-iMac:api matt$ phpunit ./tests/ONC/Test/Partridge/Import/Importer/ImportStaticTest.php
PHPUnit 5.2.1 by Sebastian Bergmann and contributors.

E..[2016-03-31 12:37:27] test.DEBUG: [PARSE]   Could not parse data String could not be parsed as XML <oxip version="7.1" created="2016-02-20 12:05:53" lastMsgId="" requestTime="0.0584"> <response request="getCategories" code="001" message="success" debug="" provider="GENERIC"> <disclaimer></disclaimer> <category id="16" displayOrder="-788" name="Football" category="FOOTBALL"/ <category id="34" displayOrder="-777" name="Tennis" category="TENNIS"/> <category id="23" displayOrder="230" name="Motor Bikes" category="MOTOR_BIKES"/> <category id="36" displayOrder="360" name="Volleyball" category="VOLLEYBALL"/> </responseBROKEN> </oxip>  [] []
.[2016-03-31 12:37:27] test.ERROR: [MAPPING] Could not map parsed response to stdClass | feed: CORAL_OPENBET, domain: ONC\Partridge\Entity\Category1, current key with cast: category, current key without cast: category, current result: array (   'id' => '16',   'displayOrder' => '-788',   'name' => 'Football',   'categoryBELL' => 'FOOTBALL', ), mappings: array (   'name' => 'name',   'category' => 'canonicalised_name',   '(int)displayOrder' => 'display_order', ), Request: http://xmlfeeds.coral.co.uk/oxi/pub?template=getCategories [] []

Answer 1

您可以使用带有虚拟回调的setOutputCallback方法在测试用例中将stdout抑制到控制台。例如：

public function testDlRegisteredUserWithoutPointAction()
{
    // Suppress StreamedResponse output to console
    $this->setOutputCallback(function() {});
    ....
}

Here更多文档。

希望这个帮助

Answer 2

虚假警报，它是我自己制作的独白实例，而不是symfony管理的实例。咄

phpunit monolog console输出太详细了

2 个答案: