Question

我希望在以下HTML结构的“2014 Spring Recreation Soccer”文本的基础上使用Xpath找到“U10 Boys”文本：

  <?php 
  if(isset($_GET['jid'])) 
  {
  $jid=$_GET['jid'];
  $status=$_GET['status'];
  if($status=='active') { $new_status='inactive'; } else { $new_status='active'; }
  $delet_query = mysql_query("UPDATE job SET status='$new_status' WHERE jid='". $jid."' ") or die(mysql_error());
  if($delet_query) {
   echo 'job with id '.$row[jid].' is activated, to refresh your page, click'.  '<a href='.$_SERVER["PHP_SELF"].' > here </a>';
   }
   }
    <table class="table table-bordered table-hover table-striped">
     <thead>
       <tr>
       <th>JOb ID</th>
       <th>CompanyID</th>
       <th>Job Description</th>
       <th>Duration</th>
       <th>Budget</th>
       <th>KeySkills</th>
       <th>Joining Date</th>
       <th>Expiry Date</th>
       <th>Min Experience</th>
       <th>Max Experience</th>
       <th>Status</th>
       <th>Set Status</th>
       </tr>
  </thead>
  <tbody>
<?php
$res=mysql_query("SELECT * FROM job ORDER BY jid DESC");
while($row=mysql_fetch_array($res))
{
?>
<tr>
<td><p><?php echo $row['jid']; ?></p></td>
<td><p><?php echo $row['cid']; ?></p></td>
<td><p><?php echo $row['jdesc']; ?></p></td>
<td><p><?php echo $row['duration']; ?></p></td>
<td><p><?php echo $row['budget']; ?></p></td>
<td><p><?php echo $row['keyskills']; ?></p></td>
<td><p><?php echo $row['jdate']; ?></p></td>
<td><p><?php echo $row['edate']; ?></p></td> 
<td><p><?php echo $row['cdexmin']; ?></p></td>
<td><p><?php echo $row['cdexmax']; ?></p></td>
<td><p><?php if($row['status']=="active") { echo "Active"; } else { echo "Inactive"; } ?></p></td>
<td><a href="?jid=<?php echo $row['jid']; ?>&status=<?php echo $row['status']; ?>"><?php if($row['status']=="active") { echo "Activate"; } else { echo "DeActivate"; } ?></a></td></tr>
<?php } ?>
</tbody>
</table>

我试过跟随Xpath，但它不起作用。

<div>
  <div>
    <table>
      <thead>
        <tr>
          <td>
            <table>
              <tbody>
                <tr>
                  <td > </td>
                  <td >
                    <span>2014 Spring Recreation Soccer</span>
                  </td>
                </tr>
              </tbody>
            </table>
          </td>
        </tr>
      </thead>
    </table>
  </div>

  <div>
    <table >
      <tbody>
        <tr >
          <td >1</td>
          <td >
            <b>
              <span >U10 Boys</span>
            </b>
          </td>
        </tr>
      </tbody>
    </table>
  </div>
</div>

Answer 1

您可以尝试这种方式：

//div[table[contains(., "2014 Spring Recreation Soccer")]/following-sibling::div[1]//span[contains(.,"U10 Boys")]

解释：

//div[table[contains(., "2014 Spring Recreation Soccer")]：在文档中的任意位置找到div元素，其中子元素table包含文字"2014 Spring Recreation Soccer"
/following-sibling::div[1]：从div开始，导航到最近的兄弟div ...
//span[contains(.,"U10 Boys")]：...并在兄弟span

"U10 Boys"

使用Xpath定位元素

1 个答案: