Question

我有这个Person类，有一些方法可以添加，删除和查看你的朋友。出于某种原因，当我想查看我的朋友时，即使我认为我正在以正确的方式调用正确的方法，也会打印最后一个Person对象（即carl），而不管方法调用中的对象规范如何。有什么问题？

这是代码：

package person;

public class Person {
    private static String name;
    private static String friends;

    public static void main(String[] args) {

        Person ted = new Person ("ted");
        Person jim = new Person ("jim");
        Person todd = new Person ("todd");
        Person tom = new Person ("tom");
        Person carl = new Person ("carl");

        // apparently I'm making a mistake here... 
        jim.addFriend(zack);
        System.out.println(jim.getFriends());
    }
    public Person (String aName) {
        name = aName;
        friends = "";
    }
    public static void addFriend(Person friend) {

        friends = friends + friend.name + " ";
    }
    public static void unFriend (Person nonFriend) {
        friends = friends.replace(nonFriend.name + " ", "");
    }
    public static String getFriends () {
        return friends;
    }

}

Answer 1

您正在使用静态变量。请试试这个。

package person;

public class Person {
    private  String name;
    private  String friends;

    public static void main(String[] args) {

        Person ted = new Person ("ted");
        Person jim = new Person ("jim");
        Person todd = new Person ("todd");
        Person tom = new Person ("tom");
        Person carl = new Person ("carl");

        // apparently I'm making a mistake here... 
        jim.addFriend(zack);
        System.out.println(jim.getFriends());
    }
    public Person (String aName) {
        name = aName;
        friends = "";
    }
    public void addFriend(Person friend) {

        friends = friends + friend.name + " ";
    }
    public void unFriend (Person nonFriend) {
        friends = friends.replace(nonFriend.name + " ", "");
    }
    public String getFriends () {
        return friends;
    }

}

Answer 2

请

private static String name;
private static String friends;

要

private String name;
private String friends;

并通过删除static

来更改方法

   public void addFriend(Person friend) {

        friends = friends + friend.name + " ";
    }
    public void unFriend (Person nonFriend) {
        friends = friends.replace(nonFriend.name + " ", "");
    }
    public String getFriends () {
        return friends;
    }

最后一个对象是打印的

2 个答案: