Question

我有以下HTML文件，用户将在其中输入用户名和密码，然后单击“提交”按钮。

<form Name ="form1" Method ="POST" ACTION = "userlogin.php" id="form1">
    <div id="main_body" class="full-width">
        <label>Username:</label>
        <input type = "text"
               id = "usernameLogin"
               name="pat_username">
        <label>Password:</label>
        <input type = "password"
               id = "passwordLogin"
               name="pat_password">
        <input type="submit" onclick="click_button_login()" value="Login" name="submit" id="submit"/>
    </div>
</form>

PHP文件应该连接到我的数据库并检查输入的用户详细信息是否正确。我之前已经测试了数据库连接。用户点击“提交”按钮后，系统会显示以下错误：Cannot POST /http-services/emulator-webserver/ripple/userapp/x/C/xampp/htdocs/xampp/glove_project_php/www/userlogin.php

<?php
if(isset($_POST["submit"])){
    $servername = "localhost";
    $username = "root";
    $password = "";
    $dbname = "dbname";

    // Create connection
    $conn = new mysqli($servername, $username, $password, $dbname);

    //Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    }


    $newUsername = mysqli_real_escape_string($conn, $_POST['pat_username']); 
    $newPassword = mysqli_real_escape_string($conn, $_POST['pat_password']);   

    $result = $conn->query("SELECT * FROM tablename WHERE patient_username ='$newUsername' AND patient_password='$newPassword'");



    if (mysqli_num_rows($result)) {
        header("Location: mainmenu.html");       
    } 
    else
    {    
        header("Location: index.html");

    }
    $conn->close();
}
?>

是否有一种不同的方法可以调用此PHP文件在模拟器上运行？此代码在localhost上完美运行。

Answer 1

为什么要检查$ _POST超全局中是否存在$ _POST [“submit”]？我相信您应该检查您发送的变量是否已设置：

变化：

if(isset($_POST["submit"]))

为：

if ((isset($_POST["pat_username"]))&&(isset($_POST["pat_password"])))

如果错误仍然存在，请告诉我。

Answer 2

  Your form, you should working on security and eliminating auto submission, this eliminates auto submission as form contains SESSION_ID() which are unique on web browsing session.

    <Form Name ="form1" Method ="POST" ACTION = "userlogin.php" id="form1">
    <div id="main_body" class="full-width">
        <br>
        <br>                      
                    <label>Username:</label>
                    <input type = "text"
                           id = "usernameLogin"
                           name="pat_username"> <br>

                <br>    <label>Password:</label>
                    <input type = "password"
                           id = "passwordLogin"
                           name="pat_password"> <br><button value="<?php echo session_id() ?>" type="submit" name="login_check">Login</button>

   </div>
   </Form>

//您的登录检查页面，存在很大的安全风险。密码应加密。请使用 SALT ， hash / md5 / sha 进行加密。而且对于查询使用sprintf就像这样只是一个例子

  ##SPRINTF EXAMPLE CODE
  //$query = sprintf('SELECT * FROM TABLE WHERE username = "%s" AND password = "%s"',mysql_real_escape_string($username),mysql_real_escape_string($password));

  #### EXAMPLE END HERE##

  <?php
  if(isset($_POST["login_check"]) && $_POST['login_check']==session_id()){
  $servername = "localhost";
  $username = "root";
  $password = "";
  $dbname = "dbname";

  // Create connection
  $conn = new mysqli($servername, $username, $password, $dbname);

  //Check connection
  if ($conn->connect_error) {
    die("Connection failed: " . $conn->connect_error);
  }


$newUsername = mysqli_real_escape_string($conn, $_POST['pat_username']); 
$newPassword = mysqli_real_escape_string($conn, $_POST['pat_password']);   

$result = $conn->query("SELECT * FROM tablename WHERE patient_username ='$newUsername' AND patient_password='$newPassword'");



if (mysqli_num_rows($result)) {
    header("Location: mainmenu.html");       
} 
else
{    
    header("Location: index.html");

}
$conn->close();
 }
?>

提交表格帖子登录

2 个答案: