将Integer转换为Binary会返回错误的值

Question

我创建了一个数字转换器，我需要将Integer转换为Binary。当我尝试转换整数12时。它为我提供了值0 0 0 0 0 1 0 0而不是0 0 0 0 1 1 0 0。

代码：

number = int(input("Enter a integer between 255 and 0: "))
    if (number > 255) or (number < 0):
        print("Please input less than 255!!!")
    else:
        a = False

        for myCounter in range (8): 

            if (number % 2 == 1):#if remainder is equal to 1
                myResult = ' 1 ' + myResult#add '1' character to the string

            else: 
                (number % 2 == 0)#if input has no remainder
                myResult = ' 0 ' + myResult#add '0' character to the string

            number = number / 2

        print("Binary equivalent is: %s" %myResult)

如何使用ROUND_HALF_UP将0.5四舍五入为1？输出如下。

任何帮助都将不胜感激！

Answer 1

代码在Python 2.7中运行良好。对于Python 3.x，请尝试将number = number/2替换为number=number//2

number = 12
a = False
myResult  = ''
for myCounter in range (8): 

    if (number % 2 == 1):#if remainder is equal to 1
        myResult = ' 1 ' + myResult#add '1' character to the string

    else: 
        (number % 2 == 0)#if input has no remainder
        myResult = ' 0 ' + myResult#add '0' character to the string

    number = number // 2

print("Binary equivalent is: %s" %myResult)