Question

我正在尝试使用Selenium Python包自动登录到GMail。但是，我无法完成任务并收到以下错误：

Traceback (most recent call last):
  File "C:\Users\Surojit\Desktop\Python\automaticpasswordFiller.py", line   21, in <module>
    passwordElem = browser.find_element_by_id('Passwd')
  File "C:\Users\Surojit\AppData\Local\Programs\Python\Python35-32\lib\site- packages\selenium\webdriver\remote\webdriver.py", line 266, in  find_element_by_id
    return self.find_element(by=By.ID, value=id_)
  File "C:\Users\Surojit\AppData\Local\Programs\Python\Python35-32\lib\site- packages\selenium\webdriver\remote\webdriver.py", line 744, in find_element
    {'using': by, 'value': value})['value']
  File "C:\Users\Surojit\AppData\Local\Programs\Python\Python35-32\lib\site-  packages\selenium\webdriver\remote\webdriver.py", line 233, in execute
    self.error_handler.check_response(response)
  File "C:\Users\Surojit\AppData\Local\Programs\Python\Python35-32\lib\site- packages\selenium\webdriver\remote\errorhandler.py", line 194, in check_response
    raise exception_class(message, screen, stacktrace)
selenium.common.exceptions.NoSuchElementException: Message: Unable to locate  element: {"method":"id","selector":"Passwd"}
Stacktrace:
    at FirefoxDriver.prototype.findElementInternal_   (file:///C:/Users/Surojit/AppData/Local/Temp/tmpceecsm46/extensions/fxdriver@goo glecode.com/components/driver-component.js:10770)
     at FirefoxDriver.prototype.findElement   (file:///C:/Users/Surojit/AppData/Local/Temp/tmpceecsm46/extensions/fxdriver@goo  glecode.com/components/driver-component.js:10779)
    at DelayedCommand.prototype.executeInternal_/h   (file:///C:/Users/Surojit/AppData/Local/Temp/tmpceecsm46/extensions/fxdriver@goo    glecode.com/components/command-processor.js:12661)
    at DelayedCommand.prototype.executeInternal_    (file:///C:/Users/Surojit/AppData/Local/Temp/tmpceecsm46/extensions/fxdriver@goo glecode.com/components/command-processor.js:12666)
    at DelayedCommand.prototype.execute/<   (file:///C:/Users/Surojit/AppData/Local/Temp/tmpceecsm46/extensions/fxdriver@googlecode.com/components/command-processor.js:12608)

我写的简单代码是：

from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
import time

browser = webdriver.Firefox()
browser.get('http://gmail.com')
action = webdriver.ActionChains(browser)
emailElem = browser.find_element_by_id('Email')
emailElem.send_keys("MyUserName")
browser.find_element_by_name('signIn').click()
#browser.get('https://accounts.google.com/ServiceLogin?         service=mail&continue=https://mail.google.com/mail/#password')
passwordElem = browser.find_element_by_id('Passwd')
passwordElem.send_keys("MyPassword")
browser.find_element_by_name('signIn').click()

另外，我试图通过将其与类似问题的答案进行比较来找出我的代码中的错误：Auto connect on my Gmail account with Python Selenium

有人可以指导我走正确的道路并让我知道我在哪里犯了错误吗？

P.S：这是我在stackoverflow上的第一篇文章。请原谅我在发布问题时所犯的任何错误

Answer 1

在2020年，使用Gmail登录要困难得多，因为Gmail将硒操作的窗口作为漫游器窗口，并会显示类似这样的消息。img of error

但是现在，我找到了一种成功的登录方式，而Google没有任何错误或警告。

您可以登录到另一个网站，因为Google会使用StackOverflow之类的其他网站或其他具有Gmail登录名的网站来接受它作为安全登录。

def gmail_sign_in(email, password):
    driver = webdriver.Chrome()

    driver.get('https://stackoverflow.com/users/signup?ssrc=head&returnurl=%2fusers%2fstory%2fcurrent')

    driver.find_element_by_xpath('//*[@id="openid-buttons"]/button[1]').click()

    driver.find_element_by_xpath('//*[@id="identifierId"]').send_keys(email)

    input = WebDriverWait(driver, 10).until(
        EC.element_to_be_clickable((By.XPATH, '//*[@id="identifierNext"]/span/span'))
    )
    input.click()

    driver.implicitly_wait(1)

    driver.find_element_by_xpath('//*[@id="password"]/div[1]/div/div[1]/input').send_keys(password)

    input = WebDriverWait(driver, 10).until(
        EC.element_to_be_clickable((By.XPATH, '//*[@id="passwordNext"]/span/span'))
    )
    input.click()
    driver.implicitly_wait(1)
    driver.get('https://www.google.com/')

希望该功能的代码是可以理解的，并输入您的电子邮件和密码，以确保您具有适当的输入。

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

Answer 2

您正在尝试查找尚未在dom中加载的元素的Passwd id。尝试添加一些延迟，以便页面可以加载。

emailElem = browser.find_element_by_id('Email')
emailElem.send_keys('MyUserName')
nextButton = browser.find_element_by_id('next')
nextButton.click()
time.sleep(1)
passwordElem = browser.find_element_by_id('Passwd')
passwordElem.send_keys('MyPassword')
signinButton = browser.find_element_by_id('signIn')
signinButton.click()

推荐方法为browser.implicitly_wait(num_of_seconds)，请参阅this

Answer 3

I hope that, it will be helpful for automate the gmail in updated chrome version.

from selenium import webdriver
import time


driver = webdriver.Chrome()
driver.get("http://gmail.com")

driver.find_element_by_id("identifierId").send_keys('your mail id')
driver.find_element_by_id("identifierNext").click()
time.sleep(5)
driver.find_element_by_name("password").send_keys('your password')
driver.find_element_by_id("passwordNext").click()
time.sleep(5)

driver.get("https://accounts.google.com/SignOutOptions?hl=en&continue=https://mail.google.com/mail&service=mail")
driver.find_element_by_xpath('//button[normalize-space()="Sign out"]').click()
driver.close()

Answer 4

您可以使用密钥来避免再搜索下一个元素

from selenium.webdriver.common.keys import Keys

   def login_gmail(email,password):

     browser.find_element_by_name('Email').send_keys(email+Keys.ENTER)
     time.sleep(2)
     browser.find_element_by_name('Passwd').send_keys(password+Keys.ENTER)

Answer 5

ID剪切的方法对我也不再有效。

我检查了文档，发现了很多其他方法来获得成功。

尝试通过NAME搜索元素，它会起作用。

password = wait.until(
EC.element_to_be_clickable((By.NAME,'password')))

CLASS_NAME

Answer 6

我有另一种解决方案，无需任何麻烦。将 Seleniumwire 与 undetected browser v2

一起使用

from seleniumwire.undetected_chromedriver.v2 import Chrome, ChromeOptions
options = {}
chrome_options = ChromeOptions()
chrome_options.add_argument('--user-data-dir=hash')
chrome_options.add_argument("--disable-gpu")
chrome_options.add_argument("--incognito")
chrome_options.add_argument("--disable-dev-shm-usage")
# chrome_options.add_argument("--headless")
driver = Chrome(seleniumwire_options=options, options=chrome_options)

# use selenium methods as usual to navigate through elements and you will be able to log in.

除此之外，seleniumwire 还有很多很棒的功能，查看 github repository

Answer 7

问题是gmail改变了登录的工作方式。您在一个页面上插入电子邮件，然后单击下一步，然后您将获得一个新页面，您可以在其中插入密码并单击登录。尝试以下操作：

from selenium import webdriver
browser = webdriver.Firefox()

browser.get('http://gmail.com')

emailElem = browser.find_element_by_id('Email')
emailElem.send_keys('MyUserName')
nextButton = browser.find_element_by_id('next')
nextButton.click()
passwordElem = browser.find_element_by_id('Passwd')
passwordElem.send_keys('MyPassword')
signinButton = browser.find_element_by_id('signIn')
signinButton.click()

Answer 8

最好的方法是在需要等待任何元素时使用显式等待。它比time.sleep(1).

更好

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

browser = webdriver.Firefox()
browser.get('http://gmail.com')
wait = WebDriverWait(browser, 10)

password_elem = wait.until(EC.presence_of_element_located((By.ID,'Passwd')))
password_elem.send_keys("MyPassword")
browser.find_element_by_name('signIn').click()

希望，这会对你有帮助。

Answer 9

你可以这样做，但我不建议像gmail这样的自动化。这不是一个好习惯。对于测试电子邮件 - 我建议使用像https://putsbox.com/

这样的工具

Answer 10

这是更新版本

def loginToGmail():
from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
from time import sleep




chrome_driver = "C:/Python37/chromedriver.exe"
browser = webdriver.Chrome(chrome_driver) 
browser.get('https://gmail.com')

if "inbox" in browser.current_url:
    print("Logged in")
else:
    identifier=WebDriverWait(browser, 30).until(EC.presence_of_element_located((By.NAME, "identifier"))) 
    identifier.send_keys(LOGIN)
    nextBtn = browser.find_element_by_id ('identifierNext')
    nextBtn.click()
    sleep(1)
    password=WebDriverWait(browser, 30).until(EC.presence_of_element_located((By.NAME, "password")))
    password.send_keys(PASSWD)
    nextBtn = browser.find_element_by_id('passwordNext')
    nextBtn.click()

    waitTimer=0
    logged=False
    while waitTimer<30 and not logged:
        sleep(1)
        waitTimer+=1
        if "inbox" in browser.current_url: 
            logged=True
            print("Logged in")

使用Python-Selenium自动登录GMAIL

10 个答案: