Question

我有以下存储库：

<?php

namespace App\Repositories;

use App\Employee;

class EmployeeRepository
{

    protected $employee;

...

    public function getAllManagersList(Employee $employee)
    {
        $managers = $employee->getAllManagers();
        $result = Array();
        foreach ($managers as $manager)
        {
            $result[$manager->id] = $manager->first_name . ' ' . $manager->last_name;
        }
        return result;
    }


}

正在调用模型：

<?php

namespace App;

use Illuminate\Database\Eloquent\Model;
use DB;

class Employee extends Model {

    protected $table = 'employees';

    public $timestamps = true;

...

    public function getAllManagers()
    {
        $managers = DB::table('employees')->select(['id','first_name','last_name'])->orderBy('last_name')->where('is_manager','=','1')->get();
        return $managers;
    }


}

我的控制器正在调用它：

public function create(EmployeeRepository $employeeRepository)
{
    $manager_list = $employeeRepository->getAllManagersList();
    //\Debugbar::info($manager_list);
    return view('employees/create')->with('manager_list',$manager_list);
}

但是当我运行这个时，我得到以下内容：

Type error: Argument 1 passed to App\Repositories\EmployeeRepository::getAllManagersList() must be an instance of App\Employee, none given, called in C:\xampp\htdocs\people\app\Http\Controllers\EmployeeController.php on line 31

我试图以一种简洁的方式得到它，以便我可以让我的模型只做db请求和我的存储库来整理它，以便它在我的页面中显示得很好。这就是我尝试将其从控制器调用到存储库到模型的原因。

Answer 1

You are calling $employeeRepository->getAllManagersList();.

But the function is defined as : public function getAllManagersList(Employee $employee).

从模型中获取的存储库不起作用

1 个答案: