将AsyncTask从类中吸引到MainActivity中

时间:2016-04-12 13:34:59

标签: java android android-asynctask

我是android开发的新手,我需要一点帮助我的代码。我必须使用类中的AsyncTask进入我的主要活动。我如何在主要功能中对其提出上诉?

我的主要活动:

public class ListActivity extends Activity implements OnItemClickListener {
ArrayList<Person> lista;
ProgressDialog progress;
private ListView lv;

public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_lista);
    lv = (ListView) findViewById(R.id.list);
    lv.setOnItemClickListener(this);

    new DataReturn().onPostExecute("random ip"); 

}

@Override
public void onItemClick(AdapterView<?> arg0, View arg1, int arg2, long arg3) {
    Person p = (Person) arg0.getItemAtPosition(arg2);
    new AlertDialog.Builder(ListActivity.this).setTitle("Information").setMessage(p.getLastName()).setPositiveButton(android.R.string.yes, new DialogInterface.OnClickListener() {
                public void onClick(DialogInterface dialog, int which) {
                    dialog.dismiss();
                }
            }).setIcon(android.R.drawable.ic_dialog_alert).show();

}

我的AsyncTask代码是:

public class DataReturn extends AsyncTask<String,Void,String> {
ArrayList<Person> rlist;
Dialog progress;
ListView rlv;
Context context;
@Override
protected void onPreExecute() {
    super.onPreExecute();
    ProgressDialog progress = new ProgressDialog(null);
    progress.setCancelable(false);
    progress.setMessage("Loading...");
    progress.setTitle("Loading");
    progress.show();
}

protected String doInBackground(String... arg0) {
    return Utils.httpGetFromUrl(arg0[0]);
}

protected void onPostExecute(String result) {
    ArrayList<Person> rlist = Utils.parseJson(result);
    // ArrayAdapter<String> arrayAdapter = new
    // ArrayAdapter<String>(ListActivity.this,
    // android.R.layout.simple_list_item_1);
    ArrayAdapter<Person> adapter = new ClassAdapter(context, rlist);
    rlv.setAdapter(adapter);    
    progress.dismiss();
}   

2 个答案:

答案 0 :(得分:1)

如果你有一个新课程,那么你这样做的方式是错误的。如果它是Mainactivity的内部类,那么这样做是正确的。

尝试以下

//Asuming there is no parameters in the constructor but context other wise 
//delete MainActivity.this

     DataReturn dataReturn = new DataReturn(MainActivity.this);
     dataReturn.execute(your random ip);

答案 1 :(得分:1)

尝试:

new DataReturn().execute("your random ip");