Question

我需要从wadl服务调用一个方法并传递一个参数

wadl: http://domain.com/application.wadl 
method: checkInfo

我该怎么做？

//Wsdl - Soap: I need to do this but with a wadl service

$wsdl = new SoapClient('http://domain.com/application?wsdl');

$wsdl->__call('checkInfo',array('data'=> ''));
//or
$wsdl->checkInfo(array('data'=> ''));

谢谢!!!!

Answer 1

您可以使用SOAP服务器执行此操作：

class MyClass{
    function checkInfo() {
        return "Hello";
    }

}
//when in non-wsdl mode the uri option must be specified
$options=array('uri'=>'http://localhost/');
//create a new SOAP server
$server = new SoapServer(NULL,$options);
//attach the API class to the SOAP Server
$server->setClass('MyClass');
//start the SOAP requests handler
$server->handle();

然后使用它：

<?php
 /*
 * PHP SOAP - How to create a SOAP Server and a SOAP Client
 */

$options = array('location' => 'http://localhost/server.php', 
                  'uri' => 'http://localhost/');
//create an instante of the SOAPClient (the API will be available)
$api = new SoapClient(NULL, $options);
//call an API method
echo $api->checkInfo();
 ?>

来自here

的代码示例

在php中使用wadl服务

1 个答案: